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MA_775_DIABLO [31]
3 years ago
6

Choose the correct answer to complete the paragraph about the acceptance of the heliocentric model. In the second century BCE, t

he Greek astronomer Ptolemy tried to explain the backward movement of the planets by using a solar system model that included . For centuries, this was the accepted model. During the Renaissance, Nicholas discovered the old heliocentric model of Aristarchus. In Aristarchus’s model, the rising and setting of the Sun was explained by the movement of the .
Chemistry
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

the first blank is epicycle.

the second blank is Copernicus

the third blank is earth

PtichkaEL [24]3 years ago
4 0

Answer:epicycles,copermicus, earth

Explanation:

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Sulfur (S) = 32, and of oxygen (O) = 16.
olganol [36]

Answer:

It should be 115.5 amu but you didnt type that as an answer choice so...

Explanation:

Bruh all you had to do was add oxygen and sulfur and subtract from the total to get your answer :D.

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Why is baking soda an ionic bond
Kaylis [27]
Because it is made up of sodium, a metal, and carbon, a nonmetal.

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6 0
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What is the H+ concentration for an aqueous solution with pOH = 4.01 at 25 ∘C? Express your answer to two significant figures an
EleoNora [17]

I believe pH = -log[H+]

Also, 14 = pH + pOH

Therefore pH = 14 - pOH

pH = 14 - 4.01

pH = 9.99

9.99 = -log[H+]

Solve for H+

5 0
3 years ago
(a) The original value of the reaction quotient, Qc, for the reaction of H2(g) and I2(g) to form HI(g) (before any reactions tak
Taya2010 [7]

Answer:

Here's what I get  

Explanation:

Assume the initial concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

We must calculate the initial concentration of HI.

1. We will need a chemical equation with concentrations, so let's gather all the information in one place.

                   H₂ +    I₂    ⇌ 2HI

I/mol·L⁻¹:    0.30   0.15         x

2. Calculate the concentration of HI

Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} =  5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}

3. Plot the initial points

The graph below shows the initial concentrations plotted on the vertical axis.

 

7 0
3 years ago
An observation that does not deal with numbers?
enyata [817]
Qualitative observation. Which is data or information with your senses such as sight, taste, smell, and touch.
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3 years ago
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