Answer:
Melting of snow
Evaporation of water from desk
Explanation:
Processes that increase the entropy of the universe are those processes that have an increased disorderliness. We should note that there are three principal states of matter which are the liquid, gas and solid. The gaseous state is the most disorderly while the solid is the least disorderly.
Now. We can see that the cooling of a hot cup of coffee is a process that needs or leads to a loss in temperature which obviously decreases disorderliness of the universe.
The melting of snow however is a process that leads to an increase in the disorderliness of the universe. It entails moving from the solid state to the liquid state. It tends to move to a more disordered state indicating an increase in the entropy of the universe.
The evaporation of water from the desk is quite similar to that above. Hence since we are moving from the liquid to the gaseous state via evaporation, we can state that the entropy of the universe has increased since we have moved from a state with a lesser degree of disorderliness to a state that is more disordered I.e from liquid to gaseous state.
Answer:
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Explanation:
i can not read it clearly
Answer:
'Oxidation states have changed.'
Explanation:
Redox Reactions can be identifiable by a change in oxidation number/states of two of the atoms in the reaction. Any reaction in which no oxidation numbers/state change is not a redox reaction.
The answer is electrolytes. Strong electrolytes like strong acids, strong bases and salts dissociate completely into ions when dissolved and no neutral molecules are present in their solution. Weak electrolytes like weak acids and weak bases do not completely ionize in water and some neutral molecules are present in their solution, while nonelectrolytes do not dissociate into ions when in solution at all.
Answer:
16L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 4L
P1 (initial pressure) = 4atm
P2 (final pressure) = 1atm
V2 (final volume) =?
Using Boyle's law equation P1V1 = P2V2, the new volume can be obtain as follow:
P1V1 = P2V2
4 x 4 = 1 x V2
16 = V2
V2 = 16L
Therefore, her new lungs volume is 16L
