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kvasek [131]
3 years ago
12

Which two physical properties allow a mixture to be separated by chromatography?

Chemistry
2 answers:
snow_tiger [21]3 years ago
7 0
<span> solubility and molecular polarity </span>
Tcecarenko [31]3 years ago
3 0

Answer:

The correct option is: (4) solubility and molecular polarity

Explanation:

Chromatography is an analytical technique which is used for the separation of various components in a given mixture.

In this process, the mixture to be separated is first dissolved in the mobile phase, which carries it through the stationary phase, thus leading to separation of the various components.

This differential separation is the result of the differential migration which is based upon the solubility and polarity of the individual components of of the given mixture.

You might be interested in
Which of the following gases will diffuse the fastest at room temperature?
maw [93]

Answer:

I am pretty sure that it is A. H2.

Explanation:

Sorry if it's wrong.

4 0
3 years ago
Calculate the number of moles in 25.0 g of each of the
mamaluj [8]

Answer:

A. 6.25moles

B. 0.78moles

C. 0.32moles

D. 0.15moles

E. 0.43moles

Explanation:

use

  • n = mass/molar mass

A. He

  • 25/4 = 6.25moles

B. O2

  • 25/32 = 0.78moles

C. Al(OH)3

  • 27+ 3(17) = 78
  • 25/78 = 0.32 moles

D. GaS3

  • 70+3(32) = 166
  • 25/166 = 0.15moles

E. C4H10

  • 4(12)+10(1) =58
  • 25/58 = 0.43moles
5 0
2 years ago
Air containing 20.0 mol% water vapor at an initial pressure of 1 atm absolute is cooled in a 1- liter sealed vessel from 200°C t
chubhunter [2.5K]

Answer:

This solution is quite lengthy

Total system = nRT

n was solved to be 0.02575

nH20 = 0.2x0.02575

= 0.00515

Nair = 0.0206

PH20 = 0.19999

Pair = 1-0.19999

= 0.80001

At 15⁰c

Pair = 0.4786atm

I used antoine's equation to get pressure

The pressure = 0.50

2. Moles of water vapor = 0.0007084

Moles of condensed water = 0.0044416

Grams of condensed water = 0.07994

Please refer to attachment. All solution is in there.

6 0
3 years ago
Why is the classification species not considered a group? (1 point)
vitfil [10]

Each species is a separate type of organism.

  • A species is a group of creatures that share similar traits. The same species of organisms are capable of sexual reproduction as well as interbreeding and producing fertile offspring. It is a fundamental unit of taxonomy and classification.
  • The system is divided into seven categories: Kingdom, Phylum or Division, Class, Order, Family, Genus, and Species. Kingdom is the most inclusive category.
  • In a group, many types of an organism can be included even if they do not share the same traits. But species is a group of organisms that share similar traits.
  • For example, human beings are species as they are all alike in physical features, way of reproduction, etc. But the animal is considered a group because it included a variety of living beings.

Therefore, Each species is not considered a group.

Learn more about taxonomy here:

brainly.com/question/1304906

#SPJ9

6 0
1 year ago
SOMEONE PLEASE HELP
Zinaida [17]

Answer:

6. 7870 kg/m³ (3 s.f.)

7. 33.4 g (3 s.f.)

8. 12600 kg/m³ (3 s.f.)

Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

1 kg= 1000g

1m³= 1 ×10⁶ cm³

Mass of iron bar

= 64.2g

= 64.2 ÷1000 kg

= 0.0642 kg

Volume of iron bar

= 8.16 cm³

= 8.16 ÷ 10⁶

= 8.16 \times 10^{ - 6} \:  kg

\boxed{density =  \frac{mass}{volume} }

Density of iron bar

=  \frac{0.0642}{8.16 \times 10^{ - 6} }

= 7870 kg/m³ (3 s.f.)

7.

\boxed{mass = density \:  \times volume}

Mass

= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

8. Volume of brick

= 12 cm³

= 12  \times  10^{ - 6}  \: m^{3}  \\  = 1.2 \times 10^{ - 5}  \: m ^{3}

Mass of brick

= 151 g

= 151 ÷ 1000 kg

= 0.151 kg

Density of brick

= mass ÷ volume

=  \frac{0.151} {1.25 \times 10^{ - 5} }  \\  = 12600 \: kg/ {m}^{3}

(3 s.f.)

6 0
3 years ago
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