You must know the concentration of the acetic acid. Suppose the concentration is 0.1 M. The solution is as follows:
CH₃COOH → CH₃COO⁻ + H⁺
I 0.1 0 0
C -x +x +x
E 0.1 - x x x
Ka = (x)(x)/(0.1 - x)
1.8×10⁻⁵ = x²/(0.1 - x)
Solving for x,
x = 1.333×10⁻³ = H⁺
pH = -log[H⁺] = -log(1.333×10⁻³)
pH = 2.88
Answer:
The answer to your question is below
Explanation:
H₂SO₄ = sulphuric acid
KOH = potassium hydroxide
This is a neutralization reaction
H₂SO₄ + 2 KOH ⇒ K₂SO₄ + 2H₂O
2 ----------- K ----------- 2
1 ----------- S ---------- 1
4 ---------- H --------- 4
6 ------------ O ---------- 6
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Answer:
Explanation:
How do I describe an ion?
<h2>an ion is an atom that has had electrons added or taken away from it.</h2><h2>they do this in order to obtain a stable electronic configuration like their closest noble gas..see Periodic Table column 18 which is also column VIIIA</h2><h2>If they gain electrons, they are negative and are called</h2><h2>ANIONS</h2><h2>if they lose electrons they are positive and are called</h2><h2>CATIONS </h2><h2 />
