Answer:
17,18
Step-by-step explanation:
let the smaller integer be "a" and the larger be "b"
Then 2b = 3a -15 ........................equ 1
but they are consecutive integers, b= a+1 ; substitute b into equ 1,thus,
2(a+1) = 3a - 15
2a + 2 = 3a-15
collect like terms,
2+15 =3a-2a
17 = a
b= a+1
b = 17+1
b=18.
The integers are 17,18
From the moment the friend passes the bicyclist, his friend covers a distance over time t of (3.63 m/s)*t.
The bicyclist covers a distance of 1/2*(2.11 m/s^2)*t^2. They meet when these distances are equal:
3.63 t = 1.055 t^2 ==> 1.055 t^2 - 3.63 t = 0
==> t = 0 s or t = 3.44 s
A=Lw
The area is 12*34, 408 sq ft.
Answer: 4x² -4
Step-by-step explanation:
First, evaluate the exponent you'll get, 
+ 4x² -5 then evaluate to get, 1+ 4x² -5. Next, subtract the numbers, 1 + 4x² -5 then to get, -4 +4x². Lastly, rearrange the terms, -4 +4x² turns into, 4x² -4!
Answer:
They are compatible
Step-by-step explanation:
The first thing is to say that an "ace" and that it is a "coarse"
"ace" is card number 1. Group A
"coarse" is a type of the deck, found from number 1 to card 13. Group B
Thus:
Calculate A U B:
1 to 13 + 1 of the other types of cards in the deck.
At intersection B:
1 of "coarse"
Therefore, if group A is compatible with group B
