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Alina [70]
3 years ago
10

Help pleasee! i have to turn this in soon

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0

b 35 is the answer sorry if I'm worng

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Jenna bought 4 composition notebooks and 3 pocket folders from the
Anettt [7]

Answer:

Step-by-step explanation:

She paid 3.42 for 3 pocket folders in total she paid 9.85 so 9.85-3.42 should give u the total for the 4 composition notebooks then you would divide that total the 9.85-3.42 which is 6.43 divided by 4 is 1.90

4 0
4 years ago
In which direction does the right side of this graph point? F(x)=3x^4-x^2+4x-2
kaheart [24]

Answer:

Positive direction (Up) \uparrow

Step-by-step explanation:

The given function is

f(x)=3x^4-x^2+4x-2

The degree of this polynomial is even.

The leading coefficient is positive 3.

The polynomial will <em>rise </em>\uparrow on the left and <em>rise </em>\uparrowon the right.

Therefore the right side of the graph of f(x)=3x^4-x^2+4x-2 points in the positive direction of the y-axis.

4 0
3 years ago
Read 2 more answers
Would really appreciate it...
Sindrei [870]

Answer:

All of the top row is invertible.

Step-by-step explanation:

Hope I helped!


5 0
4 years ago
Read 2 more answers
Keisha is having a birthday party. Her mom gave her $30 to purchase items for the party. She brought 16 party hats and 16 bags.
ludmilkaskok [199]
Keisha has $13.2 leftover
3 0
3 years ago
A line passes through (-9,-5) and (2,-4)
zlopas [31]

The point-slope form of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-9, -5) and (2, -4). Substitute:

m=\dfrac{-4-(-5)}{2-(-9)}=\dfrac{1}{11}\\\\y-(-5)=\dfrac{1}{11}(x-(-9))\\\\\boxed{y+5=\dfrac{1}{11}(x+9)}\leftarrow\boxed{\text{point-slope form}}

The standard form of a line:

Ax+By=C

y+5=\dfrac{1}{11}(x+9)                <em>multiply both sides by 11</em>

11y+55=1(x+9)

11y+55=x+9     <em>subtract 9 from both sides</em>

11y+46=x      <em>subtract 11y from both sides</em>

46=x-11y

\boxed{x-11y=46}\leftarrow\boxed{\text{standard form}}

5 0
3 years ago
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