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3 years ago

What is the greatest common factor 12,28, and 4

Mathematics

2 answers:

Alexus [3.1K]3 years ago

5 0

The GCF ( Greatest Common Factor ) of 12, 28, and 4 is 4

Alja [10]3 years ago

5 0

Answer:

The greatest common factor of 12, 28, and 4 would be 4.

Step-by-step explanation:

We will now calculate the prime factors of 28 and 12, than find the greatest common factor (greatest common divisor (gcd) of the numbers by matching the biggest common factor of 28 and 12.

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Suppose Z Varies directly with x and inversely with y, where x = 16, y = 4, when z = 32...............

Greeley [361]

A.)
Z = kx/y where k is a constant.
32 = 16k/4
k = 128/16
k = 8

z = 8x/y

b.)
Z = 8(21)/6
Z = 28

c.)
4 = 8x/48
x = 192/8
x = 24

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3 years ago

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What is one quality of rotation

Sunny_sXe [5.5K]

Answer:

Quality rotation is the act of a joint moving through a range of motion in a way that is efficient, controlled and repeatable.

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2 years ago

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Sum of interior angles of a convex 14-gon

just olya [345]

Answer: 2160°

Step-by-step explanation:

The sum of angles in a polygon is represented by the formula:

Sum = (n - 2) x 180° where n is the number of sides in the polygon

In this case, the complex polygon has 14 sides (n = 14)

So, (14 - 2) x 180°

= 12 x 180°

= 2160°

Thus, the sum of interior angles of a convex 14-gon is 2160°

3 0

3 years ago

Please help me the photo is my queston

Studentka2010 [4]

Answer:

i think it would be 30

Step-by-step explanation:

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3 years ago

Two statistics teachers both believe that each has the smarter class. To put this to the test, they give the same final exam to

SVETLANKA909090 [29]

Answer:

We conclude that there is no difference between the two classes.

Step-by-step explanation:

We are given that two statistics teachers both believe that each has a smarter class.

A summary of the class sizes, class means, and standard deviations is given below:n1 = 47, x-bar1 = 84.4, s1 = 18n2 = 50, x-bar2 = 82.9, s2 = 17

Let $\mu_1$ = mean age of student cars.

$\mu_2$ = mean age of faculty cars.

So, Null Hypothesis, $H_0$ : $\mu_1=\mu_2$ {means that there is no difference in the two classes}

Alternate Hypothesis, $H_A$ : $\mu_1\neq \mu_2$ {means that there is a difference in the two classes}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean age of student cars = 8 years

$\bar X_2$ = sample mean age of faculty cars = 5.3 years

$s_1$ = sample standard deviation of student cars = 3.6 years

$s_2$ = sample standard deviation of student cars = 3.7 years

$n_1$ = sample of student cars = 110

$n_2$ = sample of faculty cars = 75

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(47-1)\times 18^{2}+(50-1)\times 17^{2} }{47+50-2} }$ = 17.491

So, the test statistics = $\frac{(84.4-82.9)-(0)}{17.491 \times \sqrt{\frac{1}{47}+\frac{1}{50} } }$ ~ $t_9_5$

= 0.422

The value of t-test statistics is 0.422.

Now, the P-value of the test statistics is given by;

P-value = P( $t_9_5$ > 0.422) = From the t table it is clear that the P-value will lie somewhere between 40% and 30%.

Since the P-value of our test statistics is way more than the level of significance of 0.04, so we have insufficient evidence to reject our null hypothesis as our test statistics will not fall in the rejection region.

Therefore, we conclude that there is no difference between the two classes.

6 0

3 years ago