All categories

3 years ago

QUICK !! What is the image point of (-9,5) after a translation right 3 units and down 2 units ?

Mathematics

2 answers:

krek1111 [17]3 years ago

6 0

Answer:

the image point is(-6,3)

Step-by-step explanation:

HOPE THIS HELPS

klemol [59]3 years ago

5 0

Answer:

(-6,3)

Step-by-step explanation:

You might be interested in

jill has $9.96 in nickles,pennies, and dollar bills. she has 12 more pennies than nickles and fove fewer dollar bills than nickl

AleksandrR [38]

Number of pennies:P
Number of nickels:N
Number of dollar bills:D
P=N+12
N=D+5
1P+5N+100D=996
^given
Therefore
P=(D+5)+12
P=D+17
Plug back into main equation
(D+17)+5(D+5)+100D=996
Combine like terms
106D+42=996
106D=954
D=954/106=9

9 Dollar bills

N=D+5
N=(9)+5=14

14 Nickels

P=N+12
P=(14)+12=26

26 Pennies

26*1+14*5+9*100=996

Final answer:
9 Dollars
14 Nickels
26 Pennies

8 0

4 years ago

I have calculus problems that I need help with.

aleksklad [387]

a. Note that $f(x)=x^ne^{-2x}$ is continuous for all $x$ . If $f(x)$ attains a maximum at $x=3$ , then $f'(3) = 0$ . Compute the derivative of $f$ .

$f'(x) = nx^{n-1} e^{-2x} - 2x^n e^{-2x}$

Evaluate this at $x=3$ and solve for $n$ .

$n\cdot3^{n-1} e^{-6} - 2\cdot3^n e^{-6} = 0$

$n\cdot3^{n-1} = 2\cdot3^n$

$\dfrac n2 = \dfrac{3^n}{3^{n-1}}$

$\dfrac n2 = 3 \implies \boxed{n=6}$

To ensure that a maximum is reached for this value of $n$ , we need to check the sign of the second derivative at this critical point.

$f(x) = x^6 e^{-2x} \\\\ \implies f'(x) = 6x^5 e^{-2x} - 2x^6 e^{-2x} \\\\ \implies f''(x) = 30x^4 e^{-2x} - 24x^5 e^{-2x} + 4x^6 e^{-2x} \\\\ \implies f''(3) = -\dfrac{486}{e^6} < 0$

The second derivative at $x=3$ is negative, which indicate the function is concave downward, which in turn means that $f(3)$ is indeed a (local) maximum.

b. When $n=4$ , we have derivatives

$f(x) = x^4 e^{-2x} \\\\ \implies f'(x) = 4x^3 e^{-2x} - 2x^4 e^{-2x} \\\\ \implies f''(x) = 12x^2 e^{-2x} - 16x^3e^{-2x} + 4x^4e^{-2x}$

Inflection points can occur where the second derivative vanishes.

$12x^2 e^{-2x} - 16x^3 e^{-2x} + 4x^4 e^{-2x} = 0$

$12x^2 - 16x^3 + 4x^4 = 0$

$4x^2 (3 - 4x + x^2) = 0$

$4x^2 (x - 3) (x - 1) = 0$

Then we have three possible inflection points when $x=0$ , $x=1$ , or $x=3$ .

To decide which are actually inflection points, check the sign of $f''$ in each of the intervals $(-\infty,0)$ , $(0, 1)$ , $(1, 3)$ , and $(3,\infty)$ . It's enough to check the sign of any test value of $x$ from each interval.

$x\in(-\infty,0) \implies x = -1 \implies f''(-1) = 32e^2 > 0$

$x\in(0,1) \implies x = \dfrac12 \implies f''\left(\dfrac12\right) = \dfrac5{43} > 0$

$x\in(1,3) \implies x = 2 \implies f''(2) = -\dfrac{16}{e^4} < 0$

$x\in(3,\infty) \implies x = 4 \implies f''(4) = \dfrac{192}{e^8} > 0$

The sign of $f''$ changes to either side of $x=1$ and $x=3$ , but not $x=0$ . This means only $\boxed{x=1}$ and $\boxed{x=3}$ are inflection points.

4 0

1 year ago

Read 2 more answers

Blank inches equals 20 feet

Aneli [31]

The answer is 240 simply multiply 12 x 20

7 0

3 years ago

Please help meeee I’m stuck only if you know geometry

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

You can see by the markings that ST is congruent to AY, and that TA is congruent to YS. Those are 2 sides, so so far we have SS. One important thing that comes up WAY TOO OFTEN IN GEOMETRY TO IGNORE is the fact that both of those triangles share the side SA. This is called the reflexive property. The theorem for congruency between these 2 triangles is SSS.

8 0

3 years ago

10/13 = 8 - 2z/52 Thats the question. Im dyin for help. :)

svp [43]

Answer:

z = 188

Step-by-step explanation:

1. 10/13 = 8 - 2z/52 (simplify - 2z/52)

10/13 = 8 (- 1/26)*z

2. 10/13 = (- 1/26)*z + 8 (flip for ease in solving)

(- 1/26)*z + 8 = 10/13

3. (- 1/26)*z + 8 = 10/13 (inverse: subtract 8 from each side to isolate variable <em>z</em>)

(- 1/26)*z = 10/13 - (8*13)/(1*13) (common denominator needed for add/subtract)

(- 1/26)*z = - 94/13 (simplify)

4. (- 1/26)*z = - 94/13 (inverse: multiply both sides by -26/1 to isolate variable <em>z</em>)

3 0

4 years ago

Read 2 more answers