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3 years ago

5

Need help with number 27

2 answers:

mash [69]3 years ago

8 0

Hello,

Équation : 356 + 365 + x = 977
→ 731 + x = 977
→ x = 977 - 731 = ....

Bye :)

Karolina [17]3 years ago

5 0

To find this number, let's represent the unknown amount of students with the variable x:

356 + 365 + x = 977

721 + x = 977

x = 256

There are 256 students in ninth grade.

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Anyone? Help pweeez :)

Amanda [17]

So one miles for A and the fee is $170 then B is $160 then if you used company A you'd go 3 miles to match company B which their miles would be 2,

which I guess the answer would be 5 miles?

8 0

3 years ago

Please help me:( The volume of the above solid is

iren2701 [21]

Answer:

the volume of cylinder = πr²h

h = 5cm

r = 6cm

volume = π × 6² × 5

= π × 6 × 6 × 5

= 180πcm³

3 0

2 years ago

50 pts if u anser this 4 me. thanks!

eimsori [14]

Answer:

the 1 mile and 3,218 meters in step 1 should be switched

6 0

3 years ago

Read 2 more answers

The number of males in the classroom is three more than twice the number of females. Of the total number of students is 57, how

dolphi86 [110]

Answer:

Step-by-step explanation:

Given that the number of males in the classroom is three more than twice the number of females.

the total number of students is 57

Let x be the no of males then no of females = $57-x$

Also we have 3 more than twice no of females as

$2(57-x)+3$

This equals x

$2(57-x)+3=x\\114-2x+3=x\\3x=117\\x=39$

No of males = 39, no of females = 18

6 0

3 years ago

8) Find the endpoint Cif M is the midpoint of segment CD and M (2, 4) and D (5,7)

Elenna [48]

Answer:

8. c. (-1, -1)

9. a. (-6, -1)

b. True

Step-by-step Explanation:

8. Given the midpoint M(2, 4), and one endpoint D(5, 7) of segment CD, the coordinate pair of the other endpoint C, can be calculated as follows:

let $D(5, 7) = (x_2, y_2)$

$C(?, ?) = (x_1, y_1)$

$M(2, 4) = (\frac{x_1 + 5}{2}, \frac{y_1 + 7}{2})$

Rewrite the equation to find the coordinates of C

$2 = \frac{x_1 + 5}{2}$ and $4 = \frac{y_1 + 7}{2}$

Solve for each:

$2 = \frac{x_1 + 5}{2}$

$2*2 = \frac{x_1 + 5}{2}*2$

$4 = x_1 + 5$

$4 - 5 = x_1 + 5 - 5$

$-1 = x_1$

$x_1 = -1$

$4 = \frac{y_1 + 7}{2}$

$4*2 = \frac{y_1 + 7}{2}*2$

$8 = y_1 + 7$

$8 - 7 = y_1 + 7 - 7$

$1 = y_1$

$y_1 = 1$

Coordinates of endpoint C is (-1, 1)

9. a.Given segment AB, with midpoint M(-4, -5), and endpoint A(-2, -9), find endpoint B as follows:

let $A(-2, -9) = (x_2, y_2)$

$B(?, ?) = (x_1, y_1)$

$M(-4, -5) = (\frac{x_1 + (-2)}{2}, \frac{y_1 + (-9)}{2})$

$-4 = \frac{x_1 - 2}{2}$ and $-5 = \frac{y_1 - 9}{2}$

Solve for each:

$-4 = \frac{x_1 - 2}{2}$

$-4*2 = \frac{x_1 - 2}{2}*2$

$-8 = x_1 - 2$

$-8 + 2 = x_1 - 2 + 2$

$-6 = x_1$

$x_1 = -6$

$-5 = \frac{y_1 - 9}{2}$

$-5*2 = \frac{y_1 - 9}{2}*2$

$-10 = y_1 - 9$

$-10 + 9 = y_1 - 9 + 9$

$-1 = y_1$

$y_1 = -1$

Coordinates of endpoint B is (-6, -1)

b. The midpoint of a segment, is the middle of the segment. It divides the segment into two equal parts. The answer is TRUE.

4 0

4 years ago