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omeli [17]
3 years ago
10

Aiden is replacing the tile in a rectangular kitchen. The length of the kitchen is nine feet shorter than three times its width,

w. The perimeter of the kitchen is six times the width. If tiles cost $1.69 a square foot, what is the total costs to tile the kitchen?
Mathematics
2 answers:
julia-pushkina [17]3 years ago
7 0

Answer:

Total Cost of tile =  $273.28

Step-by-step explanation:

From the given information:

Let the width be = x

Then, the length of the rectangular kitchen is L = 3x - 9

The perimeter is = 6x

Suppose the cost of the tile = $1.69 a square foot.

Then the total costs to tile the kitchen is calculated as follows:

The Perimeter of the rectangle =  2(L + b)

The Perimeter of the rectangle =  2(3x - 9 + x)

The Perimeter of the rectangle =  2(4x-9)

6x = 8x - 18

- 2x = - 18

x = 18/2

x = 9

Thus, the width = x = 9 ft

the length = 3x - 9 = 3(9) - 9

the length = 27 - 9

the length = 18 ft

Area = L × W

Area = (18 × 9)ft  

Area =   162 sq. ft.

Cost of a Tile = $1.69 per sq. ft.

Thus;

Total Cost of tile = $1.69 × 162

Total Cost of tile =  $273.28

soldi70 [24.7K]3 years ago
5 0

Answer:

$273.78

Step-by-step explanation:

the other guy is wrong my dude

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Please help me! Thanks.
mars1129 [50]

Answer: Answer:

The perimeter of the polygon are

PQ = 5

RS = 5

PR = √74 = 8.60

QS = √74 = 8.60

QR = 7

Step-by-step explanation:

To calculate the perimeter of a polygon, polygon is like a coordinate with points, to find the length, we use this formula

d = √(x _2 - x_1)^2 + (y_2 - y_1)^2

Let's start from the first two vertices P ( 0 , 4) and Q(5 , 4)

x_1 = 0

y_1 = 4

x_2 = 5

y_2 = 4

PQ = √ ( 5 - 0)^2 + ( 4 - 4)^2

= √ 5^2 + 0^2

= √ 25

= 5

Between R( 5 , -3) and S ( 0 , -3)

x_1 = 5

y_1 = -3

x_2 = 0

y_2 = -3

RS = √ ( 0 - 5)^2 + ( -3 - (-3))^2

= √( -5)^2 + ( -3 + 3)^2

= √ 25 + 0

= √ 25

= 5

Between P( 0 , 4) and R (5 , -3)

x_1 = 0

y_1 = 4

x_2 = 5

y_2 = -3

PR = √( 5 - 0)^2 + ( -3 - 4)^2

= √ 5^2 + (-7)^2

= √ 25 + 49

= √ 74

= 8.60

Between Q ( 5 , 4) and S(0 ,-3)

x_1 = 5

y_1 = 4

x_2 = 0

y_2 = -3

QS = √ ( 0 - 5)^2 + ( -3 - 4)^2

= √ -5^2 + -7^2

= √ 25 + 49

= √ 74

= 8.60

Between Q( 5,4) and R(5 , -3)

x_1 = 5

y_1 = 4

x_2 = 5

y_2 = -3

QR = √ (5 - 5)^2 + ( -3 - 4)^2

= √ 0^2 + (-7)^2

= √ 0 + 49

= √ 49

= 7

Step-by-step explanation:

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Step-by-step explanation:

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X+y=0<br> 2x-3y=5 solve using elimination method
sammy [17]

Hi there!


Answer:


2x−3y=5

Add 3y to both sides of the equation.

2x=3y+5

Divide each term by 2 and simplify.

Divide each term in 2x=3y+5 by 2


2x2=3y2+52

Reduce the expression by cancelling the common factors.


Cancel the common factor.

2/x2=3y2+52 Divide x by 1


x=3y2+52



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3 years ago
Polygon ABCD has vertices A(1,3), B(1,6), C(4,6), and D(5,2)
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Answer: A (0.5, 1.5)   B(0.5, 3)    C(2, 3)    D(2.5, 1)

Step-by-step explanation:

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