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Alexus [3.1K]
2 years ago
8

Polygon ABCD has vertices A(1,3), B(1,6), C(4,6), and D(5,2)

Mathematics
1 answer:
Galina-37 [17]2 years ago
7 0

Answer: A (0.5, 1.5)   B(0.5, 3)    C(2, 3)    D(2.5, 1)

Step-by-step explanation:

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Snezhnost [94]
Its A or 6 because 30 divided by 5 is 6
5 0
3 years ago
A ECD is
FinnZ [79.3K]

Answer: SAS

Step-by-step explanation:

The Side Angle Side (SAS) postulates that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent

6 0
2 years ago
Which sequences of transformations confirm the congruence of shape II and shape I?
mylen [45]

Answer:

1. When we reflect the shape I along X axis it will take the shape I in first quadrant, and then if we rotate the shape I by 90° clockwise, it will take the shape again in second quadrant . So we are not getting shape II. This Option is Incorrect.

2. Second Option is correct , because by reflecting the shape I across  X axis and then by 90° counterclockwise rotation will take the Shape I in second quadrant ,where we are getting shape II.

3. a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin takes the shape I in fourth Quadrant. →→ Incorrect option.

4. This option is correct, because after reflecting the shape through Y axis ,and then rotating the shape through an angle of 90° in clockwise direction takes it in second quadrant.

5. A reflection of shape I across the x-axis followed by a 180° rotation about the origin takes the shape I in third quadrant.→→Incorrect option

6 0
2 years ago
Read 2 more answers
What 878.9-89.51 i need help i dont understand
Marina86 [1]

Answer: 789.39

Step-by-step explanation: Just subtract 89.51 from 878.9.

Mark Brainliest if this helped!

3 0
3 years ago
A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

            \sigma = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

                              x = 733 + 14.81

                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

8 0
2 years ago
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