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algol13
3 years ago
9

What is the value of (Negative 14 Superscript 0 Baseline) Superscript negative 2?

Mathematics
1 answer:
juin [17]3 years ago
4 0

Answer:

1

Step-by-step explanation:

We are given that an expression

{(-14)^0)^{-2}

We have to find the value of given expression.

We know that

a^0=1

Using the property

(-14)^0=1

We know that

a^{-b}=\frac{1}{a^b}

Using the property

(1)^{-2}=\frac{1}{1^2}

(1)^{-2}=1

((-14)^0)^{-2}=1

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There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.

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