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algol13
4 years ago
9

What is the value of (Negative 14 Superscript 0 Baseline) Superscript negative 2?

Mathematics
1 answer:
juin [17]4 years ago
4 0

Answer:

1

Step-by-step explanation:

We are given that an expression

{(-14)^0)^{-2}

We have to find the value of given expression.

We know that

a^0=1

Using the property

(-14)^0=1

We know that

a^{-b}=\frac{1}{a^b}

Using the property

(1)^{-2}=\frac{1}{1^2}

(1)^{-2}=1

((-14)^0)^{-2}=1

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Pleas help me solve #1 :( <br> Your answer helps so much!!
miskamm [114]

ANSWER

y = 7 \sqrt{2}

x = 7

EXPLANATION

The given triangle has a right angle.

The side opposite to the 45° angle is 7 units.

To find angle x, we use the tangent ratio.

Recall the mnemonics TOA, which means,

\tan(45 \degree)  =  \frac{opposite}{adjacent}

\tan(45 \degree)  =  \frac{7}{x}

1 =  \frac{7}{x}

x = 7

To find y, we use the sine ratio, which means

\sin(45 \degree)  =  \frac{opposite}{hypotenuse}

\sin(45 \degree)  =  \frac{7}{y}

y=  \frac{7}{\sin(45 \degree) }

y=  \frac{7}{ \frac{1}{ \sqrt{2} } }

y = 7 \times  \frac{ \sqrt{2} }{1}

y = 7 \sqrt{2}

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3 years ago
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NOP has side lengths 5 cm, 7 cm, and 9 cm. If NOP - RST, which of the following could
Iteru [2.4K]

Answer:

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3 years ago
Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = t7 + 1, y = t8
Jet001 [13]
I must assume that you meant t=1 (not t=?1).  If t=1, here's what we'd do:

1.  Find the x and y values corresponding to t=1.  They are:
      x=(1)^7+1=2     and    y=(1)^8+1=2.  (Please note:  write t^8 instead of t8,                and write t^7 instead of t7.)
2.  The slope of the tangent line to the graph is
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          dy/dx = ----------   = ---------------- with 1 substituted for t
                         dx/dt              7t^6
  
      Thus, dy/dx (at t=1) = 9/7

3.  Now we have both a point (2,2) on the graph and the slope of the tangent line to the curve at that point:  9/7

4.  The tangent line to the curve at (2,2) is  found by using the point-slope formula:

y-y1 = m(x-x1)

which comes out to y-2 = 9/7(x-2), or 7y-14 = 9(x-2).  You could, if you wished, simplify this result further (e. g., by solving for y in terms of x).
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I would like some help on this.
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