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Alex Ar [27]
4 years ago
8

Suppose that you arrive at a bus stop randomly, so all arrival times are equally likely. The bus arrives regularly every 30 minu

tes without delay (say, on the hour and on the half hour). What is the expected value of your waiting time? Explain how you got your answer.
Mathematics
1 answer:
Semmy [17]4 years ago
7 0

Answer:

E(x) = 15 minutes

Step-by-step explanation:

The random variable X (waiting time)  has a uniform distribution between the interval [0,30], because it is just as likely that you arrive in any time and then your waiting time is minimum 0 minutes and maximum 30 minutes

The expected value  of a random variable uniform is:

E(x) = \frac{a+b}{2}

      Where a and b are the interval's extremes

Thus

E(x) = \frac{0+30}{2}

E(x) = 15 minutes

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a city’s average temperature over five months is shown in the graph. which statement is not true of the data
mrs_skeptik [129]

Answer: March to April shows the least increase of average temperature.

5 0
3 years ago
A local pizzeria offers 15 toppings for their pizzas and you can choose any 3 of them for one fixed price. How many different ty
Shtirlitz [24]

Answer:

  455 or 680, depending

Step-by-step explanation:

If we assume the three choices are different, then there are ...

  15C3 = 15·14·13/(3·2·1) = 35·13 = 455

ways to make the pizza.

___

If two or three of the topping choices can be the same, then there are an additional ...

  2(15C2) +15C1 = 2·105 +15 = 225

ways to make the pizza, for a total of ...

  455 + 225 = 680

different types of pizza.

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There is a factor of 2 attached to the number of choices of 2 toppings, because you can have double anchovies and tomato, or double tomato and anchovies, for example, when your choice of two toppings is anchovies and tomato.

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nCk = n!/(k!(n-k)!)

6 0
4 years ago
Two mechanics worked on a car. the first mechanic worked for 10 hours, and the second mechanic worked for 15 hours. together the
Yuliya22 [10]
Let x and y be the rate per hour for Mechanic 1 and 2 respectively.

Then,
x+y=205 ---------- (1)
Additionally,
10x+15y = 2500 ------ (2)

Solving equations 1 and 2;
Multiply (1) by 10 and subtract two from the result,
10x+10y = 2050
10x +15 y =2500
----------------------
        -5 y = --450 => y = 450/5 = $90
Then,
x= 205-90 = $115

Therefore,
Mechanic 1 charged $115 per hour
Mechanic 2 charged $90 per hour
3 0
3 years ago
What is a proportation??<br> I need help
Elden [556K]

Answer:

what probortation?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How do I do this ? I don’t understand
juin [17]
It's just dividing out the factoring to their simplest form. 
The bold numbers are the answers that go in the circles. 

1. 16 < 8 and 2
    8 < 2 and 4
    4 < 2 and 2

2. 42 < 14 and 3
     14 < 7 and 2

3. 40 < 2 and 20
    20 < 10 and 2
    10 < 2 and 5

4. I'm not able to see the rest of the factoring tree
6 0
3 years ago
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