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Inessa05 [86]
3 years ago
5

PLEASE HELP

Mathematics
1 answer:
Mumz [18]3 years ago
6 0
If you use/make a number line, then you will see that the answer is -18 or a. When using a number line, negative = ← and positive = →.
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Simplify the expression. p(p^-7 q^3)^-2q^-3
FinnZ [79.3K]

Answer:

Step-by-step explanation:

7323

4 0
3 years ago
In each box, 20% of the total candies are grape flavored.
mrs_skeptik [129]

Answer:

9

Step-by-step explanation:

20 x 5 = 100

45/5 = 9

9 to 20 = 11

45 to 100 = 55

<u>55</u> = 5<--- Linear

11

(since the total answer is linear, the answer is right)

6 0
2 years ago
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What is the value of the expression 5ab - 2c, where a = 2, b = 3 and c=0?
Len [333]

Answer:

30

Step-by-step explanation:

5*2*3-2*0 ( when we multiply any number with zero then the result is also zero)

30-0

30

5 0
3 years ago
The length and breadth of rectangular field are 240m and 200m respectively. Find the cost of digging the field at Rs 10 per m^2​
Inga [223]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

  • The length of rectangular field = l = 240m
  • The breadth of rectangular field = w = 200m

We can determine the area of the rectangular field using the equation

A=wl

where

  • l is the length
  • w is the width

substituting  l = 240m, and  w = 200m in the formula

A=wl

A = 240 × 200

A = 48000 m²

Given that the cost of digging the field at Rs 10 per m².

Thus,

The cost of digging the field of the area 48000 m² = 10 × 48000

                                                                                     = 480000 Rs

Therefore, the total cost of digging = 480000 Rs

8 0
3 years ago
Which graph represents the solution set of and ?
Anit [1.1K]

Answer:

<h2>GRAPH III</h2>

Step-by-step explanation:

Look at the picture.

We have

y = x² - 4 → move the graph of x² 4 units down (the vertex is (0, -4))

x + y + 2 = 0   <em>subtracy x and 2 from both sides</em>

y = -x - 2 → move the graph of -x 2 units down (the y-intercept os -2)

Only graph III and IV meets these conditions.

The solution is the points of intersection of the graphs.

Therefore your answer is GRAPH III

<em />

8 0
2 years ago
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