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Neko [114]
4 years ago
12

4,7,10,13 which has an odd product

Mathematics
2 answers:
kvv77 [185]4 years ago
8 0
13 and 7 have an odd product.

Remember:
2 evens = even
1 odd 1 even = even
2 odds = odd

Hope this helps!
Flauer [41]4 years ago
6 0
7 & 13 have an odd product.

Hope this Helps!!
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m, m+1,\ m+2,\ m+3,\ m+4,\ m+5,\ m+6-\text{seven consecutive numbers}\\\\\text{The sum}\\\\m+(m+1)+(m+2)+(m+3)+(m+4)+(m+5)+(m+6)=7m+21

4 0
4 years ago
What is 840 inches converted to centimeters
lora16 [44]
2133.6 centimeters i hope i help you
6 0
3 years ago
Can you put this in order 2.3, 2.23, 2.02, 2.03, 2.22, 2.2
Vikentia [17]
2.02, 2.03, 2.2, 2.22, 2.23, 2.3 is the correct order.
6 0
3 years ago
Read 2 more answers
Solve this system of linear equations. Separate the x- and y-values with a comma. -3x=42-16y 14x=76-16y
myrzilka [38]

Answer:

(2,3)

Step-by-step explanation:

The given equations are:

1st: -3x=42-16y

2nd: 14x=76-16y

Subtract the first equation from the second one:

14x--3x=76-42-16y--16y

14x+3x=34-16y+16y

17x=34

x=\frac{34}{17}=2

We plug in x-value into the second equation to get:

14(2)=76-16y

14x=76-32

28-76=-16y

-48=-16y

Divide both sides by -16

y=3

5 0
3 years ago
The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds
Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 50

Find the probability that he weighs between 170 and 220 pounds.

This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{50}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 170

Z = \frac{X - \mu}{\sigma}

Z = \frac{170 - 200}{50}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

6 0
4 years ago
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