Answer:please correct me if I’m wrong but I believe Part A for the slopes are…
1.3/1 or 3
2.-3
3.9/5
4.4/3
Step-by-step explanation:
It’s going up 3 and “running” 1 and it’s positive since the line is going up.
Y2-y1. -16-2
————= ————=-18/6=-3
X2-x1. 8-2
You’re just finding the slope
Solve for it. If further explanation is needed please tell me.
Answer:
3xyzsquare root of xy^2
the third option
Step-by-step explanation:
look for what you cn take from all of it equally
The Tangent Line Problem 1/3How do you find the slope of the tangent line to a function at a point Q when you only have that one point? This Demonstration shows that a secant line can be used to approximate the tangent line. The secant line PQ connects the point of tangency to another point P on the graph of the function. As the distance between the two points decreases, the secant line becomes closer to the tangent line.
The least common denominator for the question you have supplied me with is 10. The least common multiple of the denominators, 5 and 10, is 10, making the LCD 10.
Answer:
your answer is 7.4 X 104 and if you further multiply then you will get 769.6
