We are going to continue the process; this time we are going to evaluate both functions at x=2.4:
For our first function:
For our second function:
To the nearest tenth:
We can conclude that the positive solution of our functions to the nearest tenth is
.
The answer is g(x) = 200 times 1.0609^x
Solution:
=200 •1.03•2x.
<span>=200•1.03^(2x). </span>
<span>1.03^2x = (1.03²)^x
= 1.0609^x
</span>
<span>g(x) = 200·1.0609^x</span>
81 * 1 / 27^y = 9 ^2y+1
81 * 1 / 9^3y/2 = 9 ^ 2y+1
9^3y/2 * 9 ^ (2y+1) = 81
9 ^ ( 3y/2 + 2y + 1) = 81 = 9^2
3y/2 + 2y + 1 = 2
7y/2 = 2 -1 = 1
7y = 2
y = 2/7 answer
Answer:hello
Step-by-step explanation:
u said a hello was needed
Just look at the 2 and the 0 in the hundred's place. There's your answer. 3.20 is greater than 3.02