Find the point on the graph of the given function at which the slope of the tangent line is the given slope.
1 answer:
Answer:
A ( -2 , 9 )
Step-by-step explanation:
<u>Idea:</u> You find the first derivative of f(x), and then set it equal to the desired slope. You'll find some x. That we will use to find the point.
f'(x) = 3x^2 + 12x + 20
f'(x) = 8
3x^2 + 12x + 20 = 8
3x^2 + 12x + 12 = 0
3 ( x^2 + 4x + 4 ) = 0
3 ( x + 2 )^2 = 0
x + 2 = 0
x = -2
So, the desired point is:
A ( -2, f(-2) ) --> A ( -2 , 9 )
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