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sashaice [31]
3 years ago
6

Find the point on the graph of the given function at which the slope of the tangent line is the given slope.

Mathematics
1 answer:
mezya [45]3 years ago
3 0

Answer:

A ( -2 , 9 )

Step-by-step explanation:

<u>Idea:</u> You find the first derivative of f(x), and then set it equal to the desired slope. You'll find some x. That we will use to find the point.

f'(x) = 3x^2 + 12x + 20

f'(x) = 8

3x^2 + 12x + 20 = 8

3x^2 + 12x + 12 = 0

3 ( x^2 + 4x + 4 ) = 0

3 ( x + 2 )^2 = 0

x + 2 = 0

x = -2

So, the desired point is:

A ( -2, f(-2) ) --> A ( -2 , 9 )

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Alexus [3.1K]

Answer:

what type? if right then

7^2+16^2=23^2

49+256=529

305≠529

so its not a right triangle

Step-by-step explanation:

7 0
3 years ago
What is 4 1/4 * 4/34 =
Natali5045456 [20]

4 1/4 = 16/4

17/4 : 4/34 =

17/4 * 4/34 =

1/2


5 0
2 years ago
A list of numbers is given <br><br><br> 32,16,8,4,2,1<br><br> Write a rule for the pattern
Sphinxa [80]
It is subtracting the current number by 1/2    OR you can divide by 2. each time.

32 / 2= 16
16 / 2=8
8/2=4
4/2=2
2/2=1

Hope this helped!
5 0
3 years ago
Read 2 more answers
Can someone help me please
valentinak56 [21]
He forgot to do the parenthesis before the exponent gets added!
4 0
3 years ago
The ratio of students to adults on a field trip is 8 to 1. Which table correctly shows this ratio for each grade?
elena-14-01-66 [18.8K]

Answer:

The table C correctly shows the ratio 8:1  for each grade

Step-by-step explanation:

Let

x ----> the number of students

y ----> the number of adults

we know that

\frac{x}{y}=\frac{8}{1}

<u><em>Verify each table</em></u>

Table A

grade 6

\frac{96}{88}=\frac{8}{1}

Multiply in cross

96(1)=8(88) ----> is not true

Table B

grade 6

\frac{96}{104}=\frac{8}{1}

Multiply in cross

96(1)=8(104) ----> is not true

Table C

<u><em>grade 6</em></u>

\frac{96}{12}=\frac{8}{1}

Multiply in cross

96(1)=8(12)

96=96 ----> is true

<u><em>grade 7</em></u>

\frac{120}{15}=\frac{8}{1}

Multiply in cross

120(1)=8(15)

120=120 ----> is true

<u><em>grade 8</em></u>

\frac{136}{17}=\frac{8}{1}

Multiply in cross

136(1)=8(17)

136=136 ----> is true

therefore

The table C correctly shows the ratio 8:1  for each grade

Table D

<u><em>grade 6</em></u>

\frac{96}{11}=\frac{8}{1}

Multiply in cross

96(1)=8(11)----> is not true

3 0
3 years ago
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