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sashaice [31]
3 years ago
6

Find the point on the graph of the given function at which the slope of the tangent line is the given slope.

Mathematics
1 answer:
mezya [45]3 years ago
3 0

Answer:

A ( -2 , 9 )

Step-by-step explanation:

<u>Idea:</u> You find the first derivative of f(x), and then set it equal to the desired slope. You'll find some x. That we will use to find the point.

f'(x) = 3x^2 + 12x + 20

f'(x) = 8

3x^2 + 12x + 20 = 8

3x^2 + 12x + 12 = 0

3 ( x^2 + 4x + 4 ) = 0

3 ( x + 2 )^2 = 0

x + 2 = 0

x = -2

So, the desired point is:

A ( -2, f(-2) ) --> A ( -2 , 9 )

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8 0
2 years ago
Divid 15 into two parts such that the sum of their reciprocal is 3/10
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Let x and y be the 2 parts of 15 ==> x + y=15 (given)

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Now we have the sum S of the 2 parts that is S = 15 and 
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