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sashaice [31]
3 years ago
6

Find the point on the graph of the given function at which the slope of the tangent line is the given slope.

Mathematics
1 answer:
mezya [45]3 years ago
3 0

Answer:

A ( -2 , 9 )

Step-by-step explanation:

<u>Idea:</u> You find the first derivative of f(x), and then set it equal to the desired slope. You'll find some x. That we will use to find the point.

f'(x) = 3x^2 + 12x + 20

f'(x) = 8

3x^2 + 12x + 20 = 8

3x^2 + 12x + 12 = 0

3 ( x^2 + 4x + 4 ) = 0

3 ( x + 2 )^2 = 0

x + 2 = 0

x = -2

So, the desired point is:

A ( -2, f(-2) ) --> A ( -2 , 9 )

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3 years ago
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A new car is purchased for 19700 dollars. The value of the car depreciates at
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Answer:

Step-by-step explanation:

We can plug this into a formula and get

5,500 = 19,700(.9075)^{?}

the .9075 comes from 1 - the depreciation value of 9.25% which converts to .0925 in decimal form.

? is what we are trying to solve for.

We can divide both sides by 19,700 and we get

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6 0
3 years ago
PLEASE IM DESPERATE<br> BRAINLIEST+THANKS***
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ANSWER

Option B

and

Option D.

EXPLANATION

The graph of the function has an amplitude of 2 and a period of

\frac{2\pi}{3}

Choose all the equation that has an amplitude of 2 and a period of

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These are:

y = 2 \sin3(x -  \frac{2\pi}{3} )

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3 0
3 years ago
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Three Texas drovers met on a highway and began to dicker as follows:
Alik [6]

Answer:

  • Jim's: 7
  • Duke's: 21
  • Hank's: 11

Step-by-step explanation:

Let J, D, and H represent the drove sizes of Jim, Duke, and Hank.

  2(H -6 + 1) = (J +6 -1) . . . . . Hank's offer

  3(D -14 +1) = (H +14 -1) . . . . Duke's offer

  6(J -4 +1) = (D +4 -1) . . . . . . Jim's offer

These equations can be simplified to ...

  2H - J = 15

  3D - H = 52

  6J - D = 21

__

<u>Solution</u>

Adding twice the second equation to the first gives ...

  2(3D -H) +(2H -J) = 2(52) +(15)

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Adding 6 times the third equation to this one gives ...

  6(6J -D) +(6D -J) = 6(21) +(119)

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  J = 7

Using this value in the third equation gives ...

  6(7) -D = 21

  42 -21 = D = 21

Using the value of J in the first equation gives ...

  2H -7 = 15

  H = (15 +7)/2 = 11

Then the solution is (J, D, H) = (7, 21, 11).

Jim's drove had 7 animals; Duke's drove had 21 animals; Hank's drove had 11 animals.

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