All categories

3 years ago

Need to solve this system of equations x+2y=11 4x+2y=38 Thank you!

1 answer:

5 0

The answer is ( 9 , 1 )

Use the substitution method.

Solve the first equation for x by subtracting 2y from both sides. x = 11-2y

Plug x = 11- 2y into the second equation to solve for y.
4 (11 -2y) + 2y = 38
44 - 8y + 2y = 38
44 - 6y = 38
-6y = -6
y = 1

Once you get a y value plug it into the first equation to solve for x.
x + 2 (1) = 11
x + 2 = 11
x = 9

You might be interested in

12<2x+2≤22 plz help me tnx

Alja [10]

Firstly, subtract 2 from all sides of this inequality: $10$

Next, divide by 2 on all sides of the inequality and your answer will be $5$ 

7 0

3 years ago

Help? I'd Appreciate it!

kondor19780726 [428]

Answer

y = (1/2)x - 1

Explanation

The first step is to get the gradient of the line.

The two points in the line are; (2,0) and (-2, -2).

Gradient = (-2 - 0)/(-2, - 2)

= -2/-4

= 1/2

To get the function we use one of the point (2,0) and a general point (x,y).

1/2 = (y - 0)/(x - 2)

1/2 = y/(x - 2)

(x - 2) = 2y

2y = x - 2

y = (1/2)x - 1

8 0

3 years ago

Given: ΔABC; b= 10; c = 14, and ∠A = 54°. Find the length of side a to the nearest whole number.

alexandr402 [8]

A² = b² + c² - 2bc cosA
a² = 10² + 14² - 2*10*14 cos54
a² = 100 + 196 - 280 * cos54
a = $\sqrt{100 + 196 - 280 * cos54}$
a = 11.46

5 0

3 years ago

Find area of a parallelogram with a height of 8 inches and a base of 14 inches

12345 [234]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{112 \: {inches} \: ^{2} }}}}}$

Step-by-step explanation:

Given,

Height of a parallelogram ( h ) = 8 inches

Base of a parallelogram ( b ) = 14 inches

Area of a parallelogram ( A ) = ?

Finding the area of a parallelogram

$\boxed{ \sf{area \: of \: parallelogram \: = \: base \: \times \: height}}$

⇒ $\sf{area \: of \: parallelogram \: = \: 14 \: \times 8}$

⇒ $\sf{area \: of \: parallelogram = 112 \: {inches}^{2} }$

Hope I helped!

Best regards! :D

4 0

3 years ago

The mean lifespan of a sylvania light bulb is 1600 hours with a standard deviation of 300 hours, an iqr of 450 hours, and a rang

IgorLugansk [536]

Given that the mean lifespan of a sylvania light bulb is 1600 hours with a standard deviation of 300 hours, an iqr of 450 hours, and a range of 690 hours. the lifespan distribution is relatively symmetric.

Since, the distribution is relatively symmetric, the measure of spread that is the best measurement is the standard deviation.

6 0

3 years ago