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3 years ago

you get 16 pointsPLEASE ANSWER i’m kinda failing so help

Mathematics

1 answer:

Alecsey [184]3 years ago

4 0

The answer is four because there's one line that is placed on the origin which makes it no solution because there's not supposed to be a line on the origin and number 1 is a solution because there are neither lines plotted on the origin and has parallel lines

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Identify the prime numbers in the following list 5 7 12 11

Elis [28]

Answer:

Step-by-step explanation:

A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.

A prime number has only two divisors: 1 and itself.

Therefore, the prime numbers are:

5, 7 and 11.

12 is not a prime because 12 = 2 × 6 = 3 × 4.

12 has six divisors: 1, 2, 3, 4, 6 and 12.

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3 years ago

Fractions to decimals like 5/37 and 2/16

Zina [86]

Answered respectively;
1) 0.13514
2) 0.125

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3 years ago

Read 2 more answers

What are the x-intercepts of x^2– 3x = 4?

Sindrei [870]

Answer:

x^2-3x=4

x^2-3x-4=0

x^2-4x+x-4=0

x(x-4)+1(x-4)=0

(x+1)(x-4)=0

x=-1,4

x- intercepts in the point (-1,0) and (4,0)

Step-by-step explanation:

3 0

3 years ago

I need help with this problem.

liberstina [14]

4050 divided by 3 = 1350
There is 4050 people in an arena and there is 3 sections of seats. How many people are in one section of seats?

6 0

3 years ago

Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando

Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is $\frac{7}{13}$ .

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = $\frac{7}{13}$

For $5 bill, expected value = $\frac{1}{13}$

For $10 bill, expected value = $\frac{3}{13}$

For $20 bill, the expected value = $\frac{2}{13}$

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is $\frac{7}{13}$ .

6 0

3 years ago

*you get 16 points*PLEASE ANSWER i’m kinda failing so help

you get 16 pointsPLEASE ANSWER i’m kinda failing so help