Answer:
The exponent of the second term (b) starts with 0 (b0 = 1) and then increases by one in each following term until it is equal to the exponent of the binomial (5).
Step-by-step explanation:
Hello,
x^3+7x^2+10x-6=x^3+3x^2+4x^2+12x-2x-6
=x²(x+3)+4x(x+3)-2(x+3)
=(x+3)(x²+4x-2)
=(x+3)(x+2-√7)(x+2+√7)
zeroes={-3,-2+√7,-2-√7}
There should be 6 per number
ex.
1234
1243
1342
1324
1432
1423
Answer:
The fifth line contains the error.
Step-by-step explanation:
Line 1 is the equation.
Lines 2, 3, and 4 are correct.
The error is in the 5th line.
The square root of a negative number is not a real number, so if this problem is solved only with real numbers, there is no solution.
If imaginary numbers are allowed, then the last line should read:
