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Andre45 [30]
3 years ago
5

Let f = {(-2.4), (-1,2), (0, 0), (1, -2), (2, -5)}

Mathematics
1 answer:
Alborosie3 years ago
7 0

Answer:

The composition is undefined.

Step-by-step explanation:

The output of f of 2 is -5 because -5 is not listed as the input in g of x the function is undefined.

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Ruby uses 7.2 pints of blue paint and white paint to paint her bedroom walls. 3/4 of this amount is blue paint, and the rest is
Nuetrik [128]

Answer:

1 4/5 or 1.8 pints are white

Step-by-step explanation:

1/4 of 7 1/5 = 1/4 x 36/5 = 36/20 or 9/5, which is 1 4/5

5 0
3 years ago
Can someone please help its due soon.ill give brainliest!
leva [86]

Answer:

18 and 6

4x= 18+6

4x=24

x=24/4

x=6

4x= 6×4

24

2x+3

6×2

12+3

15

3 0
3 years ago
Suppose Z Varies directly with x and inversely with y, where x = 16, y = 4, when z = 32...............
Greeley [361]
A.)
Z = kx/y where k is a constant.
32 = 16k/4
k = 128/16
k = 8

z = 8x/y

b.)
Z = 8(21)/6
Z = 28

c.)
4 = 8x/48
x = 192/8
x = 24
6 0
3 years ago
Read 2 more answers
If f(x)=X-3/x and g(x) = 5x – 4, what is the domain of (fog)(x)?<br><br><br> NEED HELP FAST!!
dedylja [7]

Answer:

Step-by-step explanation:

This is function composition. We will take the g function and plug it into the f function wherever we see an x. That will look like this when it's done but before it's simplified:

f(g(x))=\frac{5x-4-3}{5x-4} and that can be simplified down to

f(g(x))=\frac{5x-7}{5x-4}

The domain of this function will be all real numbers EXCEPT for the one(s) that cause the denominator to become undefined. Set the denominator equal to 0 and solve for x:

5x - 4 = 0 so

5x = 4 and

x = 4/5

In other words, D = {x | x ≠ 4/5}

6 0
3 years ago
1. Which would be a more helpful for solving the system: adding the two equations or subtracting
ira [324]

Answer:

1) Subtracting one from the other

2) x = 0.375 and y = 0.125

Step-by-step explanation:

Equation 1 :

\frac{2x+1}{2y}=7\\\\

Equation 2:

\frac{6x-1}{2y}=5

To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,

\frac{2x+1}{2y} =7\\\\2x+1=14y\\\\Multiplying\ Equation\ 1\  with\ 6\\\\12x+6=84y

Now for the second equation:

\frac{6x-1}{2y}=5\\\\6x-1=10y\\\\Multiplying\ equation\ 2\ with\ 2 \\\\12x-2=20y

Now subtracting equation 2 from equation 1

12x+6=84y\\\\12x-2=20y\\\\Subtracting\ leads\ to\\12x-12x+6-(-2)=84y-20y\\0+8=64y\\8=64y\\8/64=y\\0.125=y

now insert this value of y into any equation

lets insert it into equation 1

\frac{2x+1}{2y} =7\\\\2x+1=14y\\2x+1=14(0.125)\\2x+1=1.75\\2x=1.75-1\\2x=0.75\\x=0.75/2\\x-0.375

5 0
3 years ago
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