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mote1985 [20]
3 years ago
12

PLEASE HELP ME ASAAAAAPPPPPPPPPPPP PLEASE HELP ME FAST What is 5 x 2/3 ? A) 3 1/3 B) 3 2/5 C) 5 2/3 D) 10/15

Mathematics
2 answers:
harkovskaia [24]3 years ago
6 0

Answer:

Step-by-step explanation:

IF you calculate it right it is 3.3333333 or 3 1/3

katrin2010 [14]3 years ago
5 0

Answer:

A) 3 1/3

Step-by-step explanation:

5 x 2 = 10

10/3= 3 with a remainder of 1. That gives you 3 1/3

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The average age of 15 students is 16 years. If teacher’s age is included the average increases by 1. Find teacher’s age. (a) 30
Mrac [35]

Answer:

Age of teacher = 32 years

Step-by-step explanation:

Average age of 15 students = 16 years

Sum of age of 15 students = 16 * 15 = 240 years

Average of age 15 students and a teacher = 17 years

Sum of age  15 students and a teacher = 17 * 16 =  272 years

Age of teacher = 272 - 240 = 32 years

4 0
3 years ago
Read 2 more answers
WILL MEDAL help me if please
nordsb [41]
1. Use the FOIL method (x+9)(x+9)
First, outer, inner, last
x^{2} +9x+9x+81
Add your like terms
x^{2} +18x+81

2. When you add or subtract polynomials you add or subtract the like terms and then put them in order from largest to smallest exponents.

3. -5x(5 x^{3} +10 x^{2} -6x+3)

4. Since it is the perimeter, we add the 3 together.
(2 x^{2} +4x-3)+(-3 x^{2} -3)+(5x+19)
Add the like terms together:
2 x^{2} +(-3 x^{2} )=- x^{2}  \\ 4x+5x=9x \\ -8+(-3)+19=8
Put them in order of exponents
- x^{2} +9x+8

Hope this helps
8 0
3 years ago
14 bugs are crawling on the steps. Some of the bugs are black, and 4 are
docker41 [41]

Answer:

b  = 14-4

Step-by-step explanation:

Let the number of black bugs be b

Let the number of green bugs be g

If 14 bugs are crawling on the step, then;

b + g = 14 ....1

If there are 4 green bugs, then g = 4

Substitute g = 4 into the equation

b + g = 14

b + 4 = 14

b = 14 - 4

Hence the sentence that can be required to find the number of black bugs is b  = 14-4

8 0
3 years ago
The number of text messages sent daily by a student is a poisson random variable with parameter λ=5 .in a class with 20 independ
Rudik [331]
This problem is a combination of the Poisson distribution and binomial distribution.

First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961

For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5)   or approximately
=0.00006181
7 0
3 years ago
If s waves travel at 5 km/s how long do they take to travel 100 km
bixtya [17]
20 seconds
i feel like that is right
5 0
3 years ago
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