Question

Give the chemical symbol for the element with the ground‑state electron configuration [ Ar ] 4 s 2 3 d 1 . symbol: Determine the quantum numbers n and ℓ and select all possible values for m ℓ for each subshell of the element. 4 s n = 4 s ℓ = The possible values of m ℓ for the 4 s subshell are 0 − 1 , 0 , + 1 − 2 , − 1 , 0 , + 1 , + 2 − 3 , − 2 , − 1 , 0 , + 1 , + 2 , + 3 3 d n = 3 d ℓ = The possible values of m ℓ for the 3 d subshell are − 1 , 0 , + 1 − 2 , − 1 , 0 , + 1 , + 2 − 3 , − 2 , − 1 , 0 , + 1 , + 2 , + 3 0

Answer 1

Answer:

Sc (Scandium) has the given electronic configuration.

Explanation:

The given electronic configuration is [Ar]$4s^{2}3d^{1}$.

The last electron enters the d-subshell and hence is a d-block element known as Scandium with chemical symbol Sc.

For 4s subshell

n=4,l=0 and m ranges from -l to +l so m=0.

For 3d subshell

n=3,l=2 and m ranges from -l to +l so m can take values -2,-1,0,+1,+2

Note:

l values for subshells:

s : 0

p : 1

d : 2

f : 3 and so on.