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devlian [24]
2 years ago
6

What causes your skin to feel warm when it is in the sun on a summer day?

Chemistry
1 answer:
oksian1 [2.3K]2 years ago
8 0

Answer:

idek akxkkwskkd nwkdkekekd

You might be interested in
How many moles of glucose, C H O , can be "burned" biologically when 18.2 mol of oxygen is available? C H O (s) + 6O (g) --->
Feliz [49]
Answer:
              547.7 g of C₆H₁₂O₆

Solution:
               The balance chemical equation is as follow,

                           C₆H₁₂O₆  +  6 O₂    →    6 CO₂  +  6 H₂O

According to equation,

                         6 moles of O₂ burns  =  180.56 g of C₆H₁₂O₆
So,
                18.2 moles of O₂ will burn  =  X g of C₆H₁₂O₆

Solving for X,
                      X  =  (18.2 mol × 180.56 g) ÷ 6 mol

                      X  =  547.7 g of C₆H₁₂O₆
5 0
3 years ago
Read 2 more answers
on a hot summer day, water droplets often form on the outside of a cold glass. the water droplets form when water vapor in the a
dangina [55]


this is known as condensation when cold and warm temperatures meet


7 0
3 years ago
Help I think the answer is either A or D.
devlian [24]

Answer:

D

Explanation:

Miss Girl. Snow isn't in Nevada-

4 0
2 years ago
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What are some visible signs of an acid-base reaction?
marta [7]
I think one of the signs is <span>water and  salt are formed 

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6 0
3 years ago
Calculate a reasonable amount (mass in g) of your unknown acid to use for a titration. You will want about 30 mL of titrant to g
Vinil7 [7]

Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

Volume of base,

= 30 ml

Molarity of base,

= 0.05 m

Molar mass of acid,

= 400 g/mol

As we know,

⇒  Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}

On substituting the values, we get

⇒           0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}

⇒  Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}

⇒                                             =1.5\times 10^{-3}  

hence,

⇒  Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}

On substituting the values, we get

⇒  1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}

⇒  Mass \ of \ acid=1.5\times 10^{-3}\times 400

⇒                         =0.60 \ g

8 0
3 years ago
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