All categories

3 years ago

Boron fluoride obeys the octet rule. True or false

Chemistry

2 answers:

FromTheMoon [43]3 years ago

8 0

Answer:

True? I think.

Explanation:

Nadya [2.5K]3 years ago

7 0

True - Boron fluoride do obey the octet rule

Explanation:

BF3 follows the octet rule because Boron has 3 electrons on its outer shell and it can give out one electron each to the 3 fluorine atoms. This gives each Fluorine ion eight electrons and Boron ends up with no electrons on the outer shell.

You might be interested in

Indicate whether each of the following statements is correct or incorrect.1)Every Bronsted-Lowry acid is also a Lewis acid2)Ever

Hunter-Best [27]

Answer:

1) correct

2) incorrect

3) correct

4)incorrect

Explanation:

1) A Lewis acid is a substance that accepts a nonbonding pair of electrons.

A Bronsted-Lowry acid is a substance that donates a proton H⁺

Since the donation of a proton involves the acceptance of a pair of electrons, every Bronsted-Lowry acid is also a Lewis acid.

2)A Lewis acid not necessarily needs to have a proton to be donated.

3) Conjugated acids of weak bases are strong acids and conjugated acids of strong bases are weak acids.

4)K⁺ comes from a strong base, therefore is does not have an acidic behaviour.

4 0

3 years ago

DIRECTIONS: Use the Word Bank to answer the questions below. For questions 2 and 3 circle the correct choice.

Angelina_Jolie [31]

Explanation:

1. Electrons surround the nucleus in defined regions called orbits.

2. The shells further away from the nucleus are larger and can hold more electrons.

3. The shells closer to the nucleus are smaller and can hold less electrons.

4. The closest shell (closest to the nucleus) can hold a maximum of two electrons.

5. Once the first shell is full, the second shell begins to fill. It can hold a maximum of eight electrons.

6. Once the second shell is full, the third shell begins to fill.

7. Once the third shell contains Eighteen electrons, the fourth shell begins to fill.

8. The arrangement of electrons in shells around the nucleus is referred to as an atom's electronic configuration.

8 0

3 years ago

Draw the product of the reaction between CH3CH=CHCH3 and H2 under a platinum catalyst.

Pani-rosa [81]

Answer:

CH₃CH₂-CH₂CH₃

Explanation:

When an alkene, R-CH=CH-R reacts with H₂ in a Pt catalyst, the analogue alkane, R-CH₂-CH₂-R, is produced (Hydrogenation of alkenes via Pt/Pd catalyst)

Thus, the reaction of CH₃CH=CHCH₃ with H₂ under a platinum catalyst produce:

The analogue alkane

4 0

3 years ago

It is winter, and you want to know where it might snow today. Look at the predicted temperature for each state. Then identify th

Alona [7]

Answer:

reeeeeeeeeeeeeee

Explanation:

reeeeeeeeeeeeeeeeeeeeeee

5 0

3 years ago

Consider the following reaction: 2Mg(s)+O2(g)-->2MgO(s) delta H=-1204kJ

Pachacha [2.7K]

Answer:

a. The reaction is exothermic.

b. -87,9 kJ

c. 9,60g of Mg(s)

d. 602kJ are absorbed

Explanation:

Based on the reaction:

2Mg(s) + O₂(g) → 2MgO(s) ΔH = -1204kJ

a. The reaction is exothermic. Because ΔH<0. That means the reaction produces heat when occurs

b. 3,55g of Mg(s) are:

3,55g Mg × ( 1mol / 24,305g) = 0,146 moles of Mg(s)

As 2 moles of Mg(s) produce -1204 kJ of heat:

0,146 moles of Mg(s) × ( -1204kJ / 2mol Mg) = <em>-87,9 kJ</em>

c. If -238 kJ of heat were transferred. The moles of Mg(s) that react must be:

-238kJ × ( 2mol Mg / -1204kJ) = 0,395 moles of Mg(s). In grams:

0,395 moles × ( 24,305g / 1mol Mg) = <em>9,60g of Mg(s)</em>

d. The reverse reaction is:

2MgO(s) → 2Mg(s) + O₂(g) ΔH = +1204kJ

40,5g of MgO(s) are:

40,5g MgO × ( 1mol MgO / 40,3044g) = 1,00 moles of MgO(s)

As 2 moles of MgO absorbe 1204kJ of energy:

1,00 moles of MgO(s) × ( +1204 kJ / 2mol MgO) = <em>602kJ are absorbed</em>

I hope it helps!

7 0

3 years ago