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matrenka [14]
3 years ago
13

Boron fluoride obeys the octet rule. True or false

Chemistry
2 answers:
FromTheMoon [43]3 years ago
8 0

Answer:

True? I think.

Explanation:

Nadya [2.5K]3 years ago
7 0

True - Boron fluoride do obey the octet rule

Explanation:

BF3 follows the octet rule because Boron has 3 electrons on its outer shell and it can give out one electron each to the 3 fluorine atoms. This gives each Fluorine ion eight electrons and Boron ends up with no electrons on the outer shell.

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what is the consequence on your brain for snorting or taking amphetamines(meth/stimulant) as a 16 year old(minor)?
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5 0
3 years ago
Read 2 more answers
How many atoms of oxygen are in 4.00 moles of N2O5
SVETLANKA909090 [29]

Answer:

there are 20 oxygen atoms in 4.00 moles of Dinitrogen pentoxide

Explanation:

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8 0
3 years ago
When the products of a reaction are hotter than the reactants:
kobusy [5.1K]
A.) The reaction is Exothermic
5 0
3 years ago
A solution of NaOH is titrated with H2SO4. It is found that 20.05 mL of 0.3564 M H2SO4 solution is equivalent to 43.42 mL of NaO
Darya [45]

Answer : The concentration of NaOH is, 0.336 M

Explanation:

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.3564M\\V_1=20.05mL\\n_2=1\\M_2=?\\V_2=43.42mL

Putting values in above equation, we get:

2\times 0.3564M\times 20.05mL=1\times M_2\times 43.42mL

M_2=0.336M

Thus, the concentration of NaOH is, 0.336 M

3 0
3 years ago
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