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Olenka [21]
3 years ago
8

How many oxygen atoms are in 68.8mg Na₂S₂O₃ 5H₂O

Chemistry
1 answer:
guajiro [1.7K]3 years ago
5 0
It should be 8 O atoms. 3O atoms in Na2S2O3 and 5O atom in 5H2O.  The reason there are 5 O atoms are because the 5 in front of H2O means you multiply each atom in the compound by that number (like the distributive property). The H2 molecule becomes 10 Hydrogen atoms (5*2) and the Oxygen becomes 5 Oxygen atoms (5*1). Then you add the 5O atoms to the 3O atoms which equals 8
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In a reaction between 6.0 g of oxygen gas, 4.0 g of hydrogen gas, and 5.0 g of solid sulfur at standard temperature and pressure
nikitadnepr [17]

Answer:

The limiting reagent is the O₂

Explanation:

We can think, this reaction

2O₂(g) + H₂(g) + S(s)  →  H₂SO₄

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For 2 mole of O₂, I need to react 1 mol of H₂ and 1 mol of S

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0.093 mole of H₂ and 0.093 mole of S

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2 mole of H₂, I need (the double of O₂ and the same for S)

4 mole of O₂ ; 2 mole of S

For 1 mol of S, I need to react 1 mol of H₂ and 2 mole of O₂

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6 0
3 years ago
Could someone explain what oxidation numbers are and what these questions are asking of me?
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The oxidation state, sometimes referred to as oxidation number, describes the degree of oxidation of an atom in a chemical compound.

<u>Explanation:</u>

The oxidation number of an atom is the charge that atom would have if the compound was composed of ions. 1. The oxidation number of an atom is zero in a neutral substance that contains atoms of only one element. The oxidation number of simple ions is equal to the charge on the ion.

The oxidation number of a mono atomic ion equals the charge of the ion. The oxidation number of H is +1, but it is -1 in when combined with less electro negative elements. The oxidation number of O in compounds is usually -2, but it is -1 in peroxides. The oxidation number of a Group 1 element in a compound is +1.

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