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Whitepunk [10]
3 years ago
12

The mean for this set of data is 95 what is the missing number 103,99,90,86,105,96,__

Mathematics
1 answer:
Gwar [14]3 years ago
4 0
The mean is just the arithmetic average:

(103+99+90+86+105+96+x)/7=95

(579+x)/7=95

579+x=665

x=86
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Rudik [331]

Answer:

a) E(y) = 0.8

b) The average subcharge is $165

Step-by-step explanation:

We are given the following distribution in the question:

y:           0        1        2         3

P(y):   0.50   0.25   0.20   0.05

a) E(y)

E(y) = \displaystyle\sum y_iP(y_i)\\\\E(y) = 0(0.50)+1(0.25)+2(0.20)+3(0.05)\\E(y) = 0.8

b) Expected value of subcharge

Subcharge =

\$110y^2

Expected value of subcharge =

=110E(y^2)\\\\=110\displaystyle\sum y_i^2P(y_i)\\\\=110(0^2(0.50)+1^2(0.25)+2^2(0.20)+3^2(0.05))\\=110(1.5)=165

Thus, the average subcharge is $165

5 0
3 years ago
Mia has
Serggg [28]

Answer:

2 7/8

Step-by-step explanation:

first step is making these into improper fractions for example 6 1/8 would equal 49/8 because 6*8=48 and add the 1/8 to get 49/8 then do the same with the 3 1/4 make them into 8ths. so it would be 3 2/8 then 26/8 now subtract 49-26 to get 23/8. now simplify to get 2 7/8

5 0
2 years ago
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Please help! Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact valu
Nadya [2.5K]

Answer:

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Step-by-step explanation:

Given that the figure is made up of portion of a square and a semicircle, we have;

BC ≅ AB = 6 cm

The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²

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The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²

The area of the figure = The area of semicircle BC + The area of triangle ABC

The area of the figure = 4.5·π cm² + 18 cm² = \dfrac{9 \cdot \pi +36}{2} \ cm^2.

5 0
3 years ago
8 + z = 19. step equations
steposvetlana [31]

Answer:

11

Step-by-step explanation:

First subtract

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So solution would be

Z=11

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