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exis [7]
2 years ago
5

Am trying to find the value of r 1/r + 2/1-r = 4/r^2

Mathematics
1 answer:
Mashcka [7]2 years ago
6 0
<span>1/r + 2/1-r = 4/r^2

1-r+2r/r(1-r)=4/r^2
(1+r)/r(1-r)=4/r^2   cancle r both side

1+r/1-r=4/r

cross multiply 
r+r^2=4-4r
r^2+4r+r-4=0
r^2+5r-4=0
r^2+4r+r-4=0
solve it for r factor it...



</span>
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PLEASE HELPPPP. I really need it
GalinKa [24]

Answer:

Option 4: (0, 5]

Step-by-step explanation:

Given the <u>inequality notation</u>, 0 < <em>x</em> ≤ 5 :

<h2><u>Definitions:</u></h2><h3>open- and closed-parenthesis "(  )"</h3>

We know that using the <u>open- and closed-parenthesis</u>, "(  )" are used to express interval notation for which the endpoints are <em><u>not</u></em> included as part of the solution.  Hence, the open- and closed-parenthesis are associated with the inequality symbols, <em>less than </em>(>) or greater than (<), as you do not include the endpoints when these inequality symbols are used.

<h3>open- and closed-brackets "[     ]"</h3>

In contrast, the <u>open- and closed-brackets</u>, "[     ]" are used to express interval notation for which the endpoints <u><em>are</em></u> included as part of the solution.  Hence, the open- and closed-parenthesis are associated with the inequality symbols, <em>less than or equal to </em>(≤), and <em>greater than</em><em> </em><em>or equal to</em> (≥).

<h2><u>Explanation:</u></h2>

In the inequality notation, 0 < <em>x</em> ≤ 5, the endpoints are 0 and 5.  

The inequality symbol <u>between 0 and x</u> is "<," which means that we must use an open parenthesis, " ( " for the endpoint, 0.

While the inequality symbol <u>between x and 5</u> is "≤," which means that we must use an closed bracket, " ] " for the endpoint, 5.

Therefore, the correct answer is Option 4: (0, 5].

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2 years ago
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The answer is D
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Write the equation 4x + 8y = -24 in slope-intercept form
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A new video game is expected to sell 102 copies the first hour at a local game store. After that, the sales will follow the func
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8 0
3 years ago
Read 2 more answers
The point P(6, –1) is translated according to the rule (x, y) → (x – 5, y – 2).
monitta

The <em>resulting</em> point by considering that P(x, y) = (6, - 1) and P'(x, y) = P(x, y) + (- 5, - 2) is equal to the coordinates P'(x, y) = (1, - 3). (Right choice: C)

<h3>How to determined a resulting point by translation</h3>

In this question we need to determine the new location of a point by using a <em>translation</em> formula. Translations are rigid transformations in which a point is translated on a <em>Cartesian</em> plane. We have the following formula:

P'(x, y) = P(x, y) + (- 5, - 2)     (1)

Where:

  • P(x, y) - Original point
  • P'(x, y) - Resulting point

If we know that P(x, y) = (6, - 1), then the resulting point is:

P'(x, y) = (6, - 1) + (- 5, - 2)

P'(x, y) = (1, - 3)

The <em>resulting</em> point by considering that P(x, y) = (6, - 1) and P'(x, y) = P(x, y) + (- 5, - 2) is equal to the coordinates P'(x, y) = (1, - 3). (Right choice: C)

To learn more on translations: brainly.com/question/17152175

#SPJ1

6 0
2 years ago
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