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exis [7]
2 years ago
5

Am trying to find the value of r 1/r + 2/1-r = 4/r^2

Mathematics
1 answer:
Mashcka [7]2 years ago
6 0
<span>1/r + 2/1-r = 4/r^2

1-r+2r/r(1-r)=4/r^2
(1+r)/r(1-r)=4/r^2   cancle r both side

1+r/1-r=4/r

cross multiply 
r+r^2=4-4r
r^2+4r+r-4=0
r^2+5r-4=0
r^2+4r+r-4=0
solve it for r factor it...



</span>
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I’m confused on this one
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Greetings!

The formula for the area of any triangle is as followed:

A_{triangle}=\frac{bh}{2}

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<u>Let Statements:</u>

Let the variable...

→ b represent the length of the base of the triangle

→ h represent the length of the height of the triangle

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Using the information provided from the question, we can substitute its values in place of the variables and solve for the last remaining variable:

10=\frac{(4)(x+3)}{2}

Distribute the parenthesis<em> (The Distributive Property) </em>:

10=\frac{((4)(x)+(4)(3))}{2}

10=\frac{4x+12}{2}

Reduce the fraction to lowest terms:

10=2x+6

Add -6 to both sides of the equation:

(10)+(-6)=(2x+6)+(-6)

4=2x

Divide both sides of the equation by 2:

\frac{4}{2}=\frac{2x}{2}

2=x

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The Answer to this Problem is:

\boxed{x=2}

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I hope this helped!

-Benjamin

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