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Vikki [24]
3 years ago
15

Anyone who the answer to this ?

Mathematics
1 answer:
abruzzese [7]3 years ago
5 0
A. Is the answer first choice
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Emma spent $26 on her dinner with friends. She leaves a 15% tip. How much tip will Emma leave?
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$3.90

Step-by-step explanation:

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3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
olga nikolaevna [1]

f(x_1,\ldots,x_n)=x_1+\cdots+x_n=\displaystyle\sum_{i=1}^nx_i

{x_1}^2+\cdots+{x_n}^2=\displaystyle\sum_{i=1}^n{x_i}^2=4

The Lagrangian is

L(x_1,\ldots,x_n,\lambda)=\displaystyle\sum_{i=1}^nx_i+\lambda\left(\sum_{i=1}^n{x_i}^2-4\right)

with partial derivatives (all set equal to 0)

L_{x_i}=1+2\lambda x_i=0\implies x_i=-\dfrac1{2\lambda}

for 1\le i\le n, and

L_\lambda=\displaystyle\sum_{i=1}^n{x_i}^2-4=0

Substituting each x_i into the second sum gives

\displaystyle\sum_{i=1}^n\left(-\frac1{2\lambda}\right)^2=4\implies\dfrac n{4\lambda^2}=4\implies\lambda=\pm\frac{\sqrt n}4

Then we get two critical points,

x_i=-\dfrac1{2\frac{\sqrt n}4}=-\dfrac2{\sqrt n}

or

x_i=-\dfrac1{2\left(-\frac{\sqrt n}4\right)}=\dfrac2{\sqrt n}

At these points we get a value of f(x_1,\cdots,x_n)=\pm2\sqrt n, i.e. a maximum value of 2\sqrt n and a minimum value of -2\sqrt n.

6 0
3 years ago
1. Which equation represents the relationship shown in the table below? (1 point)
Alex17521 [72]
The third one is correct
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3 years ago
Identify the value of c in the following quadratic function f (x) = -2x^2+ 3x – 4
Hitman42 [59]

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-4

Step-by-step explanation:

Given function

f(x) = -2x² + 3x - 4

Comparing with ax² + bx + c We get

c = - 4

Hope it will help :)❤

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2 years ago
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i really need help with this oneeeee.Mickey went to the mall to buy new sneakers. the store was having a 60% off sale. Mickey pa
Ray Of Light [21]

Answer:

180                                                  

Step-by-step explanation:

3 0
3 years ago
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