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4 years ago

5

Viola makes gift baskets for Valentine's day. She has 13 baskets left over from last year, and she plans to make 12 more each da

y. If she has 15 work days until the day begins to sell the baskets, how many baskets will she have to sell ?

1 answer:

barxatty [35]4 years ago

4 0

Viola has 13 already.

She is going to work 15 days and make 12 each day. 15 x 12 = 180 new baskets.

Add the old and the new - 13 + 180 = 193 baskets total.

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The correct solution to the limits of x in the tiles can be seen below.

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<h3>What are the corresponding limits of x?</h3>

The limits of x approaching a given number of a quadratic equation can be determined by knowing the value of x at that given number and substituting the value of x into the quadratic equation.

From the given diagram, we have:

1.

$\mathbf{ \lim_{x \to 9^+} (\dfrac{|x-9|}{-x^2-34+387}) }$

So, x - 9 is positive when x → 9⁺. Therefore, |x -9) = x - 9

$\mathbf{ \lim_{x \to 9^+} (\dfrac{x-9}{-x^2-34+387}) }$

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$\mathbf{ \lim_{x \to 8^-} (\dfrac{8-x}{|-x^2-63x+568|}) }$

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$\mathbf{=\dfrac{1}{8+71} }$

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$\mathbf{ \lim_{x \to 7^+} (\dfrac{|-x^2-17x+168| }{x-7}) }$

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$\mathbf{ \lim_{x \to 7^+} (-x-24)}$

$\mathbf{ \lim_{x \to 7^+} (-7-24)}$

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$\mathbf{ \lim_{x \to 6^-} (\dfrac{|x-6| }{-x^2-86x+552}) }$

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$\mathbf{ \lim_{x \to 6^-} (\dfrac{1}{x+92}) }$

$\mathbf{ \lim_{x \to 6^-} (\dfrac{1}{6+92}) }$

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Learn more about calculating the limits of x here:

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