All categories

4 years ago

What is the exponenet in the expression 2.5281010101010101010

Mathematics

2 answers:

Elena L [17]4 years ago

7 0

Answer:

2.528×10^8

Step-by-step explanation:

german4 years ago

3 0

Answer:

Step-by-step explanation:

2.528×10^8

You might be interested in

Name a plane parallel to DBF.

cestrela7 [59]

Answer:

C.CAE

because those two planes never touch

5 0

3 years ago

0.5 as a fraction in lowest term

Nadusha1986 [10]

Seriously?

.5 = 5/10 = 1/2 reduced

3 0

3 years ago

Read 2 more answers

Y = x + 8 <br>4x – 2y = -12

Paha777 [63]

Answer:

x = 14

y = 22

Step-by-step explanation:

y = x + 8

4x - 2y = -12

Solve

_____________

Since we see that the first equation has y alone, we can substitute it into the values of y in the second equation.

4x - 2(x + 8) = -12

Distribute :

4x - (2(x) + 2(8)) = -12

4x - 2x +16 = -12

Combine like terms :

2x + 16 = -12

Subtract 16 from both sides :

2x = -28

Divide 2 from both sides to get x alone :

x = 14

Now that we know what x is, substitute it in the first equation to get y :

y = (14) + 8

y = 22

6 0

3 years ago

Read 2 more answers

Rudolph and the other reindeer are pulling Santa's sleigh that has a mass 1

finlep [7]

Answer:

it is 4.2 n

Step-by-step explanation:

because you have to divide 525/125=4.2

7 0

3 years ago

If X is a r.v. such that E(X^n)=n! Find the m.g.f. of X,Mx(t). Also find the ch.f. of X,and from this deduce the distribution of

astraxan [27]

$M_X(t)=\mathbb E(e^{Xt})$
$M_X(t)=\mathbb E\left(1+Xt+\dfrac{t^2}{2!}X^2+\dfrac{t^3}{3!}X^3+\cdots\right)$
$M_X(t)=\mathbb E(1)+t\mathbb E(X)+\dfrac{t^2}{2!}\mathbb E(X^2)+\dfrac{t^3}{3!}\mathbb E(X^3)+\cdots$
$M_X(t)=1+t+t^2+t^3+\cdots$
$M_X(t)=\displaystyle\sum_{k\ge0}t^k=\frac1{1-t}$

provided that $|t|$ .

Similarly,

$\varphi_X(t)=\mathbb E(e^{iXt})$
$\varphi_X(t)=1+it+(it)^2+(it)^3+\cdots$
$\varphi_X(t)=(1-t^2+t^4-t^6+\cdots)+it(1-t^2+t^4-t^6+\cdots)$
$\varphi_X(t)=(1+it)(1-t^2+t^4-t^6+\cdots)$
$\varphi_X(t)=\dfrac{1+it}{1+t^2}=\dfrac1{1-it}$

You can find the CDF/PDF using any of the various inversion formulas. One way would be to compute

$F_X(x)=\displaystyle\frac12+\frac1{2\pi}\int_0^\infty\frac{e^{itx}\varphi_X(-t)-e^{-itx}\varphi_X(t)}{it}\,\mathrm dt$

The integral can be rewritten as

$\displaystyle\int_0^\infty\frac{2i\sin(tx)-2it\cos(tx)}{it(1+t^2)}\,\mathrm dt$

so that

$F_X(x)=\displaystyle\frac12+\frac1{2\pi}\int_0^\infty\frac{\sin(tx)-t\cos(tx)}{t(1+t^2)}\,\mathrm dt$

There are lots of ways to compute this integral. For instance, you can take the Laplace transform with respect to $x$ , which gives

$\displaystyle\mathcal L_s\left\{\int_0^\infty\frac{\sin(tx)-t\cos(tx)}{t(1+t^2)}\,\mathrm dt\right\}=\int_0^\infty\frac{1-s}{(1+t^2)(s^2+t^2)}\,\mathrm dt$
$=\displaystyle\frac{\pi(1-s)}{2s(1+s)}$

and taking the inverse transform returns

$F_X(x)=\dfrac12+\dfrac1\pi\left(\dfrac\pi2-\pi e^{-x}\right)=1-e^{-x}$

which describes an exponential distribution with parameter $\lambda=1$ .

6 0

3 years ago

What is the exponenet in the expression 2.528*10*10*10*10*10*10*10*10

What is the exponenet in the expression 2.5281010101010101010