All categories

3 years ago

When the driver is disturbed by emotions this manifest itself by decreased risk behavior true or false?

Physics

1 answer:

Alina [70]3 years ago

5 0

I believe your answer is false

You might be interested in

I need help with these questions ☺️☺️

Mariana [72]

Answer:

1. well the value may vary because of different reactions to the technology because its new to a lot of people but to younger ones its something normal and something we cant live without but with older ones its something that they have lived without for most of there life.

Explanation:

6 0

3 years ago

Damian is texting while driving and ends up slamming into the back end of the car in front of him, which then strikes the car in

Sphinxa [80]

The answer for this question is negative externality

3 0

2 years ago

You place a box weighing 200.2 N on a inclined plane that makes a 37.1 angle with the horizontal. Compute the component of the g

salantis [7]

Answer:

141.56 N.

Explanation:

Data given:

Weight of the box= 200.2 N

Angle with the horizontal= 37.1°

Solution;

Gravitational force on the box, $F_g$ = weight of the box

= 200.2 N

Component of gravitational force along plane = $F_g * sin$ ( ∅ )

= W * (sin∅)

= (200.1) * sin (37.1°)

= 141.56 N

8 0

3 years ago

A quantity found by multiplying the force by the distance moved

Andrej [43]

The quantity that is calculated from the product of the force and the distance traveled due to the force is called work. It has SI units of Joules (J) which is equivalent to Newton-meter (N-m). It is the energy that happens when an object is being moved by an external force.

7 0

3 years ago

What is the car's speed at the bottom of the dip?The passengers in a roller coaster car feel 50% heavier thantheir true weight a

Rashid [163]

Answer:

v = 14 m/s

Explanation:

given,

radius of dip = 40 m

The passengers in a roller coaster car feel 50% heavier than their true weight.

Apparent weight

$A = W + \dfrac{W}{2}$

$A =\dfrac{3W}{2}$

$A =\dfrac{3mg}{2}$

When the car is at the bottom, the weight will be acting downwards and the centripetal force will also be acting downward where as Normal force which is apparent weight will be acting in upward direction.

now,

$N = m g + \dfrac{mv^2}{r}$

$\dfrac{3mg}{2} = m g + \dfrac{mv^2}{r}$

$\dfrac{mg}{2} = \dfrac{mv^2}{r}$

$v = \sqrt{\dfrac{rg}{2}}$

$v = \sqrt{\dfrac{40\times 9.8}{2}}$

v = 14 m/s

8 0

2 years ago