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Inessa [10]
3 years ago
5

In which of the following situations would the least work have been done?

Physics
1 answer:
yawa3891 [41]3 years ago
3 0
<span>
Work = (magnitude of the force) x (distance in the direction of the force)

A 100-N force lifts an object 3 m.                ==>  (100 x 3) = 300 joules

B. A 250-N force moves an object 1 m.      ==>  (250 x 1) = 250 joules

C. A 25-N force moves an object 8 m.        ==>  (25 x 8)  =  200 joules

D. A 600-N force is applied to an object
    and moves it 0 m.                                   ==>  (600 x 0) = no work
</span>                                                                           Winner ! Least work.

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Answer:

460.52 s

Explanation:

Since the instantaneous rate of change of the voltage is proportional to the voltage in the condenser, we have that

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separating the variables, we have

dV/V = kdt

integrating both sides, we have

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Since the instantaneous rate of change of the voltage is -0.01 of the voltage dV/dt = -0.01V

Since dV/dt = kV

-0.01V = kV

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Given that the voltage decreases by 90 %, we have that the remaining voltage (100 % - 90%)V₀ = 10%V₀ = 0.1V₀

So, V = 0.1V₀

Thus

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to find the time, t it takes the voltage to decrease by 90%, we taking natural logarithm of both sides, we have

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