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andrew11 [14]
3 years ago
5

A uniform electric field is oriented in the −z direction. The magnitude of the electric field is 6500 N/C.

Physics
1 answer:
nignag [31]3 years ago
5 0

Answer:

In a plane parallel to the xy plane.

Explanation:

Direction of uniform electric field is oriented in the −z direction.

a) We know that the direction of equipotential surfaces are always normal to electric field direction. So, equipotential surface will be in a plane perpendicular to electric field that in a plane perpendicular to z-axis that is parallel to the xy plane.

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A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of
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Resistivity is given by \rho=\frac {AR}{L} where A is cross-sectional area, R is resistance, L is the length and \rho is the reistivity. Substituting 0.0625 for R, 3.14 × 10-6 for A and 3.5 m for L then the resistivity is equivalent to

\rho=\frac {3.14\times 10^{-6}\times 0.0625}{3.5}=5.60714285714285714285714285714285714285\times 10^{-8}\approx 5.6\times 10^{-8}\ Ohm.m

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