Ask question

Ask question

All categories

3 years ago

8

An object of mass 20g taken at a height of 2m above the ground. Which type of energy is possessed by the object at this height ?

Calculate the value of this energy?

1 answer:

In-s [12.5K]3 years ago

7 0

<h3><u>Given</u> </h3>

Mass of an object is $\bf\red{20 g}$
Height of the body is $\bf\green{2 m}$

<h3><u>To Find</u></h3>

Value of the energy

<h3><u>Solution</u></h3>

${\purple {\underline{\boxed{\sf{ Potential\: Energy \:=\: mgh}}}}}$

Where,

$\sf\red{m}$ = Mass
$\sf\green{g}$ = Gravity
$\sf\blue{h}$ = Height

Now, Converting gram to kg

$\longrightarrow\:$ 1000g = 1kg

$\longrightarrow\:$ 20g = $\sf\dfrac{20}{1000}$

$\longrightarrow\:$ = 0.02 kg

According to the question

$\sf\red{Mass \:= \:0.02 kg}$

$\sf\green{Gravitational \;force \:= \;10 m/s^{2}}$

$\sf\purple{Height\: =\: 2 m}$

Putting these values

$\to\:$ Potential Energy = mgh

$\to\:$ Potential Energy = 0.02 × 10 × 2

$\to\:$ Potential Energy = 0.2 × 2

$\to\:$ Potential Energy = $\bf\pink{0.4\:joules}$

You might be interested in

A train at a constant 79.0 km/h moves east for 27.0 min, then in a direction 50.0° east of due north for 29.0 min, and then west

ivolga24 [154]

Answer:

Magnitude of avg velocity, $|v_{avg}| = 18.9 km/h$

$\theta' = 56.85^{\circ}$

Given:

Constant speed of train, v = 79 km/h

Time taken in East direction, t = 27 min = $\frac{27}{60} h$

Angle, $\theta = 50^{\circ}$

Time taken in $50^{\circ}$ east of due North direction, t' = 29 min = $\frac{29}{60} h$

Time taken in west direction, t'' = 37 min = $\frac{27}{60} h$

Solution:

Now, the displacement, 's' in east direction is given by:

$\vec{s} = vt = 79\times \frac{27}{60} = 35.5\hat{i} km$

Displacement in $50^{\circ}$ east of due North for 29.0 min is given by:

$\vec{s'} = vt'sin50^{\circ}\hat{i} + vt'cos50^{\circ}\hat{j}$

$\vec{s'} = 79(\frac{29}{60})sin50^{\circ}\hat{i} + 79(\frac{29}{60})cos50^{\circ}\hat{j}$

$\vec{s'} = 29.25\hat{i} + 24.54\hat{j} km$

Now, displacement in the west direction for 37 min:

$\vec{s''} = - vt''hat{i} = - 79\frac{37}{60} = - 48.72\hat{i} km$

Now, the overall displacement,

$\vec{s_{net}} = \vec{s} + \vec{s'} + \vec{s''}$

$\vec{s_{net}} = 35.5\hat{i} + 29.25\hat{i} + 24.54\hat{j} - 48.72\hat{i}$

$\vec{s_{net}} = 16.03\hat{i} + 24.54\hat{j} km$

(a) Now, average velocity, $v_{avg}$ is given:

$v_{avg} = \frac{total displacement, \vec{s_{net}}}{total time, t}$

$v_{avg} = \frac{16.03\hat{i} + 24.54\hat{j}}{\frac{27 + 29 + 37}{60}}$

$v_{avg} = 10.34\hat{i} + 15.83\hat{j}) km/h$

Magnitude of avg velocity is given by:

$|v_{avg}| = \sqrt{(10.34)^{2} + (15.83)^{2}} = 18.9 km/h$

(b) angle can be calculated as:

$tan\theta' = \frac{15.83}{10.34}$

$\theta' = tan^{- 1}\frac{15.83}{10.34} = 56.85^{\circ}$

6 0

3 years ago

Two forces are applied to a car in an effort to accel-

mestny [16]

Answer:

R=2F

Explanation:

As the forces are in same direction so the resultant force will be:

R=F+F

R=2F

4 0

3 years ago

A pendulum is observed to complete 20 full cycles in 60 seconds. Determine the period and the frequency of the pendulum.

Delvig [45]

i hope i have been useful buddy.

good luck ♥️♥️

5 0

3 years ago

Read 2 more answers

Gravity is _____ force between objects that are moving closer to one another.

pishuonlain [190]

Gravity is a pair of forces of attraction between every
two objects. Period !

It doesn't matter whether they're moving together, moving apart,
moving gracefully in synchrony, or at rest. The gravitational forces
of attraction between them are always there.

4 0

3 years ago

4. How does density affect refraction of a lightwave?

Brums [2.3K]

optical density would increase the refraction angle going in to the material

there may be a relation between opt density and mass density ... kg/m^3

7 0

3 years ago