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lana [24]
2 years ago
8

An object of mass 20g taken at a height of 2m above the ground. Which type of energy is possessed by the object at this height ?

Calculate the value of this energy?​​
Physics
1 answer:
In-s [12.5K]2 years ago
7 0
<h3><u>Given</u> </h3>
  • Mass of an object is \bf\red{20 g}
  • Height of the body is \bf\green{2 m}
<h3><u>To Find</u></h3>
  • Value of the energy

<h3><u>Solution</u></h3>

{\purple {\underline{\boxed{\sf{ Potential\: Energy \:=\: mgh}}}}}

Where,

  • \sf\red{m} = Mass
  • \sf\green{g} = Gravity
  • \sf\blue{h} = Height

Now, Converting gram to kg

\longrightarrow\: 1000g = 1kg

\longrightarrow\: 20g = \sf\dfrac{20}{1000}

\longrightarrow\: = 0.02 kg

According to the question

\sf\red{Mass \:= \:0.02 kg}

\sf\green{Gravitational \;force \:= \;10 m/s^{2}}

\sf\purple{Height\: =\: 2 m}

Putting these values

\to\: Potential Energy = mgh

\to\: Potential Energy = 0.02 × 10 × 2

\to\: Potential Energy = 0.2 × 2

\to\: Potential Energy = \bf\pink{0.4\:joules}

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luda_lava [24]
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3 years ago
A cord of negligible mass runs around two massless, frictionless pulleys. A canister with mass m = 20 kg hangs from one pulley.
photoshop1234 [79]

(a) 196 N

The equation of the forces on the side of the cord where the force F is applied is:

F-T=0 (1)

where T is the tension in the cord.

On the other side of the cord, the equation of the forces on the canister is

T-mg = ma (2)

where

m = 20 kg is the mass of the canister

g=9.8 m/s^2 is the acceleration of gravity

a is the acceleration

From (1),

T=F

Substituting into (2),

F-mg = ma\\F=m(g+a)

We want the canister to move at constant speed, so

a = 0

And therefore:

F=mg=(20)(9.8)=196 N

b) 2.0 cm

The cord is inextensible, this means that the acceleration of its parts are the same. Therefore, the acceleration of the free end must be the same as the acceleration of the canister: and this means that the two parts also cover the same distance in the same time.

Therefore, the free end of the cord must be moved exactly the same as the canister, by 2.0 cm.

c) 3.92 J, the same

The work done by the tension in the cord is

W_T = T d

where

T is the tension

d = 2.0 cm = 0.02 m is the displacement

As we said in part (a), the tension in the cord is equal to the force applied to the free end:

T = F

So

T = 196 N

Therefore, the work done by the tension is

W=(196)(0.02)=3.92 J

And since the force applied (F) is the same, then the work done by you when pulling the cord is exactly the same.

(d) -3.92 J

The weight of the canister is

F_g = mg =(20 kg)(9.8 m/s^2)=196 N

However, the direction of the force of gravity is opposite to the displacement. Therefore, the work done by gravity is negative:

W_g = - F_g d

And substituting,

W_g=-(196)(0.02)=-3.92 J

(e) Zero

The net work done on the canister can be simply calculated by adding the work done by the tension in the cord and the weight of the canister:

W=W_T+W_g = 3.92 + (-3.92 ) = 0

This is in agreement with the work-energy theorem, which states that the work done on an object is equal to its change in kinetic energy. In this situation, the canister is moving at constant speed, so its kinetic energy is not change: therefore,

\Delta K = 0 (change in kinetic energy = 0)

and so, the work done on it is also zero.

(f) The pulley system changes the direction of the force applied

This is a simple pulley system, which means  that the system does not multiply the force applied in input. In fact, the mechanical advantage of the system is

MA=\frac{F_{out}}{F_{in}}

where:

F_{out} is the output force, which is the weight of the canister

F_{in} is the force in input, which is F

So, the mechanical advantage is 1:

MA=\frac{196 N}{196 N}=1

From a point of view of energy, therefore, there is no advantage in this system.

However, the advantage offered by the pulley system concerns the direction of the force: in fact, it changes the direction of the applied force (which is F, downward) into the tension of the cord (which is upward on the canister).

6 0
3 years ago
An egg suspended above the ground has 93.1 J of gravitational potential energy. The egg is then dropped and falls to the ground.
Marina86 [1]

93.1 J of kinetic energy

3 0
3 years ago
Dina has a mass of 50 kilograms and is waiting at the top of a ski slope that’s 5.0 meters high.
Over [174]
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So we solve for v:

m*g*h=(1/2)*m*v², masses cancel out,

g*h=(1/2)*v², we multiply by 2,

2*g*h=v² and take the square root to get v

√(2*g*h)=v, we plug in the numbers and get:

v=9.9 m/s. 

So Dina's maximum velocity on the bottom of the ski slope is v=9.9 m/s.
8 0
2 years ago
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Two dogs are pulling on a chew toy. One dog pulls the chew toy with 64 N [E] and
PIT_PIT [208]

Answer:

Eastward, at 11 m/s^2

Explanation:

64N-31N=unbalanced force of 33N

F=ma

33N=(3kg)a

a=11m/s^2 to the East

3 0
2 years ago
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