Answer:
the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.
Explanation:
This problem asks that we determine whether or not a critical flaw in a wide plate is subject to detection given the limit of the flaw detection apparatus (3.0 mm), the value of KIc (98.9 MPa m), the design stress (sy/2 in which s y = 860 MPa), and Y = 1.0.

Therefore, the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.
Answer:
Acceleration
Explanation:
I think so & hope it will help yuh!
Answer:
The mass of 0.02 m³ of gold is 386 kilograms
Explanation:
Given:
The density of the gold = 19300 kg/m³.
The volume of gold = 0.02 m³
To Find:
The mass of gold = ?
Solution:
We know that density is mass divided per unit volume.
Thus mathematically
Density = \frac{mass}{volume}Density=
volume
mass
Rewriting in terms of mass ,
Mass = density * volume
On substituting the known values
Mass = 19300 kg/m³ * 0.02 m³
Mass = 386 kilograms
Learn more about Mass and Density:
Mass=?,volume=190,density=4
Mass 350 kg volume 175 density ans
This is not my answer I copied it but hope it helps:)
The correct answer is C) towards the center of the circle.
Although the object is moving at a constant speed it is constantly accelerating due to the constant change in direction as it describes the circular path. This causes a constant change in velocity as velocity is a vector quantity.
For the object to maintain the circular path there has to be centripetal force acting on the object and this centripetal force is directed towards the center of the circle.
Answer:
600m
Explanation:
30×20 at a constant speed is 600m.