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Salsk061 [2.6K]
3 years ago
14

Describe what you would do to prepare 100.0g of a 3.5% solution of ammonium sulfate in water.

Chemistry
1 answer:
frozen [14]3 years ago
7 0
<span>It'd just be 3.5g NH4SO4 added to 96.5g of H2O</span>
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6 0
3 years ago
How many moles of electrons must be transferred to plate out 110 g of manganese (MW ~ 55g/mol) from a solution of permanganate (
ololo11 [35]

Answer:

14 mol e⁻

Explanation:

Step 1: Write the balanced half-reaction for the reduction of permanganate to manganese

8 H⁺(aq) + 7 e⁻ + MnO₄⁻(aq) ⇒ Mn(s) + 4 H₂O(l)

Step 2: Calculate the moles corresponding to 110 g of manganese

The molar mass of Mn is 55 g/mol.

110 g × 1 mol/55 g = 2 mol

Step 3: Calculate the number of moles of electrons needed to produce 2 moles of Mn

According to the half-reaction, 7 moles of electrons are required to produce 1 mole of Mn.

2 mol Mn × 7 mol e⁻/1 mol Mn = 14 mol e⁻

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olga_2 [115]

<u>Hydrogen bonds </u>are weak bonds that are not strong enough to hold atoms together to form molecules but are strong enough to form bonds within and around large molecules.

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brainly.com/question/10904296

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Answer:

Fluorine

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