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steposvetlana [31]
2 years ago
8

Need these solved ASAP please​

Chemistry
1 answer:
satela [25.4K]2 years ago
5 0

Explanation: SHHHSHHH

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What is the a property of a base
Savatey [412]
Bases have a Ph do gretater than 7
They are bitter in taste
They are soapy texture
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What is a specialized
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2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
3 years ago
The law of conservation of mass is applicable to
katrin2010 [14]

Answer:

The law of conservation of mass states that in a closed system, mass is neither created nor destroyed during a chemical or physical reaction. The law of conservation of mass is applied whenever you balance a chemical equation.

Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

It is applicable in a chemical when the the mass of the products in a chemical reaction is equal to  the mass of the reactants.

But it is not applicable in a nuclear fusion as some of the mass is generated as energy.

3 0
3 years ago
If 17.8 grams of KOH dissolve in enough water to make a 198-gram solution, what is the concentration in percent by mass?
sleet_krkn [62]
Solute of solution = 17.8 g

Solvn = 198 g

% = 17.8 / 198

w% = 0.089 x 100 = 8.9%  by mass

hope this helps!
7 0
3 years ago
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