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denpristay [2]
3 years ago
15

Calcular el numero de gramos de un mol de metano

Chemistry
1 answer:
mart [117]3 years ago
3 0

Answer:

metano= CH4

C= 12 g/mol

H= 1g/mol x 4 = 4g/mol

CH4= 12g/mol + 4g/mol = 16g/mol

(las masas están aproximadas).

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Which energy source is considered nonrenewable?
iragen [17]

Answer:

Fossil fuel

Explanation:

4 0
3 years ago
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At 1 atm, how much energy is required to heat 39.0 g of h2o(s at –24.0 °c to h2o(g at 121.0 °c?
earnstyle [38]
Q = mcΔt, q = energy [J] m = mass (of water) [g]; c = specific heat capacity of water [J g⁻¹ K⁻¹/°C⁻¹]; Δt = change in temperature [K/°C]
Δt = 121 - -24 = 145
q = 39 × 4.18 × 145
q = 23637.9 J
4 0
3 years ago
A good team member will actively listen, which means they will ______.
Wittaler [7]
B is the answer I think better sure
8 0
3 years ago
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15 POINTS PLS HELP!!!!!
scZoUnD [109]

Answer: (C) Vaporizing

Explanation:

 Vaporization is the process in which the substance change the state of of liquid into the gas state.

The vaporization process require the largest input of the energy as when the state is in the solid state then, the solid substances contain the strong forces of the attraction and they require high energy to break these strong bonds.

For changing the liquid state into the gases state we require to overcome the surface tension and require enough energy for acquiring the vaporization state.

Therefore, option (C) is correct.

5 0
3 years ago
An ore is to be analyzed for its iron content by an oxidation-reduction titration with permanganate ion. A 4.230 g sample of the
Leya [2.2K]

Answer:

See explanation

Explanation:

The balanced redox reaction equation is;

8H+ + MnO4^- + 5Fe2+ ---------> Mn2+ + 5Fe3+ + 4H2O

Amount of KMnO4 reacted = 31.60/1000 * 0.05120 = 1.62 * 10^-3 moles

From the reaction equation;

1 mole of MnO4^- reacted with 5 moles of Fe2+

1.62 * 10^-3 moles will react with 1.62 * 10^-3 moles * 5/1 = 8.1 * 10^-3 moles

Mass of Fe2+ reacted = 8.1 * 10^-3 moles  *  56 g/mol

Mass of Fe2+ reacted = 0.45 g

Amount of iron in the sample =  0.45 g

Percentage of iron in the sample;

0.45 g/4.230 g  * 100 = 10.6 %

8 0
2 years ago
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