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disa [49]
4 years ago
13

If 59.3 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced?

Chemistry
1 answer:
KIM [24]4 years ago
8 0
Moles of KClO₃ = 59.3 / (39 + 35.5 + 16 x 3)
Moles of KClO₃ = 0.48

Molar ratio of KClO₃ to O₂ = 2 : 3

Moles of O₂ produced = 1.5 x 0.48
= 0.72

Mass of O₂ = moles x Mr
= 0.72 x 32
= 23.04 grams
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Read the statement.
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g The decomposition reaction of A to B is a first-order reaction with a half-life of 2.42×103 seconds: A → 2B If the initial con
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t=\frac{2.303}{k}\log\frac{[A_o]}{[A]} ......(2)

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