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3 years ago

HURRYYY!!!!!!!!!!

Chemistry

1 answer:

vlabodo [156]3 years ago

8 0

Im not sure but i think its 350. I really hope im right

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Why are metals good conductors of electric current

castortr0y [4]

An electric current can be carried through a metal by the free flow of the shared electrons.

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3 years ago

Read 2 more answers

2 H2 + 2 NO → N2 + 2 H2O the observed rate expression, under some conditions, is: rate = k[NO]2 Which of the following mechanism

guapka [62]

Explanation:

Rate law is defined as the rate of a reaction is directly proportional to the concentration of reactants at constant temperature.

$Rate \propto [\text{concentration of reactant}]^{n}$

= k $[\text{concentration of reactant}]^{n}$

where, k = rate constant

n = order of reaction

For the given reaction, $2H_{2} + 2NO \rightarrow N_{2} + 2H_{2}O$

Hence, its rate will be as follows.

Rate = $k[H_{2}][NO]$

Also, it is known that slowest step in a chemical reaction is the rate determining step.

Hence, for the given rate law correct reaction is as follows.

Step 1 : $H_{2} + NO \rightarrow N + H_{2}O$ (slow)

Balancing this equation it becomes $H_{2} + 2NO \rightarrow N_{2}O + H_{2}O$ (slow)

Step 2: $N_{2}O + H_{2} \rightarrow N_{2} + H_{2}O$ (fast)

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3 years ago

An object was measured by a worker as

Gre4nikov [31]

Answer:

$\boxed{2.8 \, \%}$

Explanation:

$\text{Percent error} = \dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \, \%$

Data:

Predicted = 17.4 cm

Actual = 17.9 cm

Calculation:

$\text{Percent error} = \dfrac{\lvert 17.4 - 17.9\lvert}{17.9} \times 100 \, \% \\\\= \dfrac{\lvert-0.5\lvert}{17.9} \times 100 \, \% = \dfrac{0.5}{17.9} \times 100 \, \% \\\\= 0.028 \times 100 \, \% = \textbf{2.8 \%}\\\\\text{The percent error in the measurement is } \boxed{\textbf{2.8 \%}}$

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3 years ago

Ionic compound of GaTe

kow [346]

Answer:

Gallium(II) telluride

Explanation:

3 0

3 years ago

The automobile fuel called E85 consists of 85% ethanol and 15% gasoline. E85 can be used in so-called flex-fuel vehicles (FFVs),

Zolol [24]

Answer:

49,736.84 kJ

Explanation:

1 L of gasoline has 0.70 kg

1,5 L of gasoline has x kg

1 L - 0.70 kg

1.5 - x

x = 0.7 *1.5 = 1,05 kg

1 mol of gasoline has 114 g

y mol of gasoline has 1050 g

1 mol - 114 g

y - 1050 g

y = $\frac{1050}{114}$ = 9.21 mol

1 mol of gasoline has a combustion heat of 5400 kJ

9.21 mol of gasoline has a combustion heat of z

z = 5400 * 9.21 = 49,736.84 kJ

8 0

3 years ago