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Luba_88 [7]
3 years ago
12

Read the statement.

Chemistry
1 answer:
Rudiy273 years ago
6 0

Answer:

300 gr.

Explanation:

if 204gr/100gr=solubility, then according to the condition solubility=612/x.

It means, 204/100=612/x, where x=612*100/204=300 gr.

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A liquid solvent is added to a flask containing an insoluble solid. The total volume of the solid and liquid together is 93.0 mL
shutvik [7]

Answer:

Mass of solid = 189.141 gram

Explanation:

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7 0
3 years ago
What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?
kompoz [17]

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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\text{Number of moles}=\frac{0.610g}{78g/mol}

Number of moles of Al(OH)_3 = 0.0078 moles

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Chemical equation for the above reaction follows:

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

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1 mole of  Al(OH)_3 reacts with 3 moles of HCl

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Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

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Mass of HCl required will be = 0.8541 grams

3 0
3 years ago
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