Answer:
5
Explanation:
Let us look at the values very closely. It is easy to see that the first to the fifth ionization energies of the element are closely related to each other. Recall that the ionization energy increases as the the number of electrons removed from the outermost shell of the atom increases. Hence E1<E2<E3......... The first five ionization energies suggest the removal of valence shell electrons.
However, the sixth and seventh ionization energies shows a jump, the ionization energy suddenly increases by a very high magnitude. This can not suggest the removal of a valence shell electron but the removal of inner or core electrons. Hence the answer.
Answer:
For NADH; P:O = 2.5
For FADH
₂; P : O = 1.5
Explanation:
The P:O (phosphate:oxygen) ratio represents the amount of inorganic phosphate, Pi used per atom of oxygen consume to synthesize ATP.
The Chemiosmotic theory predicts H⁺:O and H⁺:ATP ratios. Experimentally these appear to be 10 and 4 respectively when NADH is the substrate, equivalent to a P:O ratio of 2.5, and 6 and 4 respectively for FAD-linked substrates (e.g. succinate), equivalent to a P:O ratio of 1.5.
1. Electron flow from NADH to O₂ pumps protons at three sites to yield 3 ATP (P:O = 2.5)
For NADH: 10 H
⁺ translocated/O (2e
-)
ATP/2e
- = (10 H⁺/ 4 H
+) = 2.5
2. Succinate (via FADH2) bypasses site 1 giving 2 ATP (P : O = 1.5)
For FADH
₂= 6 H
⁺/O(2e
-
)
ATP/2e
- = (6 H
+/ 4 H
+) = 1.5
Answer:
300 0.24
600 0.46
900 0.70
1200 0.95
1500 1.20
Explanation: correct on behavior gasses tutorial
A molecule is larger because it is a bond of atoms.
