Answer:
Explanation:
1)
Given data:
Number of moles of aluminium = 0.223 mol
Mass of silver produced = ?
Solution:
Chemical equation:
3AgNO₃ + Al → 3Ag + Al(NO₃)₃
Now we will compare the moles of Al with silver.
Al : Ag
1 : 3
0.223 : 3×0.223= 0.669 mol
Grams of silver:
Mass = number of moles × molar mass
Mass = 0.669 mol × 107.87 g/mol
Mass = 72.2 g
2)
Given data:
Number of moles of mercury(II) oxide produced = 3.12 mol
Mass of mercury = ?
Solution:
Chemical equation:
2Hg + O₂ → 2HgO
Now we will compare the moles of mercury with mercury(II) oxide.
HgO : Hg
2 : 2
3.12 : 3.12
Mass of Hg:
Mass = number of moles × molar mass
Mass = 3.12 mol × 200.59 g/mol
Mass = 625.84 g
3)
Given data:
Number of moles of dinitrogen pentoxide = 12.99 mol
Mass of oxygen = ?
Solution:
Chemical equation:
2N₂ + 5O₂ → 2N₂O₅
Now we will compare the moles of N₂O₅ with oxygen.
N₂O₅ : O₂
2 : 5
12.99 : 5/2×12.99 = 32.48 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 32.48 mol × 32 g/mol
Mass = 1039.36 g
4)
Given data:
Number of moles of benzene = 0.103 mol
Mass of carbon dioxide = ?
Solution:
Chemical equation:
2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O
Now we will compare the moles of N₂O₅ with oxygen.
C₆H₆ : CO₂
2 : 12
0.103 : 12/2×0.103 = 0.618 mol
Mass of carbon dioxide:
Mass = number of moles × molar mass
Mass = 0.618 mol × 44 g/mol
Mass = 27.192 g
