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3 years ago

What sign shoes dissolving

Chemistry

2 answers:

almond37 [142]3 years ago

8 0

Answer: can u explain ur question please?

Explanation:

Alexxandr [17]3 years ago

7 0

Answer:

dividing you mean?

this can mean divide / or ÷

Explanation:

You might be interested in

Given the following acids and their Ka values: Phenol, C6H5OH Ka = 1.00 × 10-10 Acetic acid, CH3CO2H Ka = 1.80 × 10-5 Nitrous ac

Ierofanga [76]

Answer:

$NO_2^-$ < $CH_3COO^-$ < $C_6H_5O^-$

Explanation:

$K_a$ value is a measure of acidic strength. The larger the $K_a$ value, the stronger is the acid and the weaker is the conjugate base.

The given $K_a$ values are as follows -

Phenol = $1\times 10^-^1^0$

Acetic acid = $1.80 \times 10^-^5$

Nitrous acid = $4.50 \times 10^-^4$

Order of increasing acid strength will be -

Phenol < Acetic acid < Nitrous acid

Strongest acid will have weakest conjugate base so the order of increasing base strength will be -

$NO_2^-$ < $CH_3COO^-$ < $C_6H_5O^-$

4 0

4 years ago

If CO2 is not removed by boiling the solution after the addition of HCl, how will this affect the amount of NaOH required to rea

zimovet [89]

Answer:

See explanation

Explanation:

CO2 reacts with water to form carbonic acid as follows;

CO2(g) + H2O(l) ---------> H2CO3(aq)

This makes the solution more acidic hence it will require more NaOH to reach end point due to the increase in acidity.

Hence, if CO2 is not removed by boiling the solution, a greater amount of NaOH is required to reach end point.

6 0

3 years ago

The atomic mass of an atom can be found by

sashaice [31]

The answer to this question is A

8 0

3 years ago

A research team has just discovered a new element called Likhitium. Now they need to determine the average atomic mass in order

earnstyle [38]

The question is incomplete, the complete question is shown in the image attached to this answer.

Answer:

139.13

Explanation:

The average atomic mass of the element Likhitium is the sum of the relative abundance of all the isotopes of Likhitium.

We obtain the relative atomic mass of Likhitium as follows;

(44.7/100 * 138) + (52.3/100 * 139) + (0.5/100 * 140) + (2.5/100 * 141)

61.7 + 73.2 + 0.7 + 3.53 = 139.13

Hence the relative abundance of Likhitium is 139.13

6 0

3 years ago

04.05 mol

victus00 [196]

Answer:

34.8 g

Explanation:

Answer:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 123.90 70.91 208.24

P₄ + 20Cl₂ ⟶ 4PCl₅

Mass/g: 46.0 32.0

2. Calculate the moles of each reactant

$\text{moles of P}_{4} = \text{46.0 g P}_{4} \times \dfrac{\text{1 mol P}_{4}}{\text{123.90 g P}_{4}} = \text{0.3713 mol P}_{4}\\\\\text{moles of Cl}_{2} = \text{32.0 g Cl }_{2} \times \dfrac{\text{1 mol Cl }_{2}}{\text{70.91 g Cl }_{2}} = \text{0.4513 mol Cl }_{2}$

3. Calculate the moles of PCl₅ we can obtain from each reactant

From P₄:

The molar ratio is 4 mol PCl₅:4 mol P₄

$\text{Moles of PCl}_{5} = \text{0.3713 mol P}_{4} \times \dfrac{\text{4 mol PCl}_{5}}{\text{4 mol P}_{4}} = \text{0.3713 mol PCl}_{5}$

From Cl₂:

The molar ratio is 4 mol PCl₅:20 mol Cl₂

$\text{Moles of PCl}_{5} = \text{0.4513 mol Cl}_{2}\times \dfrac{\text{4 mol PCl}_{5}}{\text{20 mol Cl}_{2}} = \text{0.090 26 mol PCl}_{5}$

4. Identify the limiting and excess reactants

The limiting reactant is chlorine, because it gives the smaller amount of PCl₅.

The excess reactant is phosphorus.

5. Mass of excess reactant

(a) Moles of P₄ reacted

The molar ratio is 1 mol P₄:20 mol Cl₂

$\text{Moles reacted} = \text{0.4513 mol Cl}_{2} \times \dfrac{\text{4 mol P}_{4}}{\text{20 mol Cl}_{2}} = \text{0.090 26 mol P}_{4}$

(b) Mass of P₄ reacted

$\text{Mass reacted} = \text{0.090 26 mol P}_{4} \times \dfrac{\text{123.90 g P}_{4}}{\text{1 mol P}_{4}} = \text{11.18 g P}_{4}$

(c) Mass of P₄ remaining

Mass remaining = original mass – mass reacted = (46.0 - 11.18) g = 34.8 g P₄

4 0

3 years ago