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Llana [10]
3 years ago
14

A research team has just discovered a new element called Likhitium. Now they need to determine the average atomic mass in order

to complete the entry on the periodic table. Given the following relative abundances, what is the average atomic mass of Likhitium?
Chemistry
1 answer:
earnstyle [38]3 years ago
6 0

The question is incomplete, the complete question is shown in the image attached to this answer.

Answer:

139.13

Explanation:

The average atomic mass of the element Likhitium is the sum of the relative abundance of all the isotopes of Likhitium.

We obtain the relative atomic mass of Likhitium as follows;

(44.7/100 * 138) + (52.3/100 * 139) + (0.5/100 * 140) + (2.5/100 * 141)

61.7 + 73.2 + 0.7 + 3.53 = 139.13

Hence the relative abundance of Likhitium is 139.13

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Katyanochek1 [597]

Answer:

0.912 mL

Explanation:

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FeCl3 is the limiting reactant.

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Hence actual yield of Iron III sulphide = 0.043 moles

Theoretical yield of Iron III sulphide = actual yield ×100%/ %yield

Theoretical yield of iron III sulphide= 0.043 ×100/75 = 0.057 moles of Iron III sulphide

From the reaction equation,

2moles of iron III chloride produced 1 mole of iron III sulphide

x moles of iron III chloride, will produce 0.057 of iron III sulphide

x= 2× 0.057= 0.114 moles of iron III chloride

But

Volume= number of moles/ concentration

Volume= 0.114/0.125

Volume= 0.912 mL

4 0
3 years ago
Please someone help mee
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Answer:

13.9kj/mol

Explanation:

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Explanation:

Given,

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