Answer:
The pressure of CO2 = 0.48 atm
Explanation:
Step 1: Data given
Kp = 0.23
Step 2: The balanced equation
2NaHCO3(s) ↔ Na2CO3(s) + CO2(g) + H2O(g)
Step 3: Calculate the pressure of CO2
Kp = (p(CO2))*(p(H2O))
For 1 mol CO2 we have 1 mol H2O
x = p(CO2) = p(H2O)
Kp = 0.23 = x*x
x = √0.23
x = 0.48
pCO2 = x atm = 0.48 atm
The pressure of CO2 = 0.48 atm
Because it goes from a somewhat solid state to a liquid state.
The molecular weight is between 70 and 85. Let's accidentally pick some quantity in amid, like 78.
7.74% of 78 is how many 'u' there are of H:
78 u * 7.74% = 78 u * .0774 = 6.0372 u
The only hydrocarbon below that has 6 hydrogens is C6H6. We can even check this answer:
Total u = 6C + 6H
= 6(12.01) + 6(1.0079)
= 78.11 u
6(1.0079) / 78.11 * 100 = 7.74%
These would be your answers!
(taken from a source)
Follow the scientific method
Keep detailed records
Communicate experimental results
Hope that helped!
:)
