Answer:
B
Keep the temperature at 20°C. Stir the solution
Explanation:
Answer:
The answer to your question is: 1, 2, 1, 2
Explanation:
1 Fe(s) + 2 Na⁺(aq) → 1 Fe²⁺(aq) + 2 Na(s)
Fe⁰ - 2e⁻ ⇒ Fe⁺² Oxidases
Na⁺ + 1 e⁻ ⇒ Na⁰ Reduces
1 x ( 1 Fe⁰ ⇒ 1 Fe⁺²) Interchange number of
2 x ( 2Na⁺ ⇒ 2 Na⁰ ) electrons
Answer:
<u>∆H° reaction = -890.3 kJ</u>
Explanation:
The given equation is :
Now ,
O2 is in the standard state so its ∆H° is zero.
∆H° is calculated by considering the formation of CO2 , H2O and CH4 .
..........∆H°a = -393.5 kJ
.....∆H°b = -285.8 kJ
..........∆H°c = -74.8 kJ
Multiply equation of water H2O by 2
and reverse the direction of equation of CH4
Hence the sign of ∆H°c = +74.8 kJ becomes +ve.
We are doing this because CH4 is to be in the reactant side not in the product side.
∆H° reaction = ∆H°a +2(∆H°b) -∆H°c
∆H° reaction = -393.5 - 2(285.8) + 74.8
∆H° reaction = -890.3 kJ
Answer:
a) COCl₂.
b) The molecular formula is COCl₂.
Explanation:
To obtain empirical formula of phosgene you should divide elemental compositions over atomic mass of each atom, and divide these results between the smallest, thus:
C = 12,14%/12,01 = 1,01
O = 16,17%/16 = 1,01
Cl = 71,69%/35,45 = 2,02
Empirical formula:
C = 1,01/1,01 = 1
O = 1,01/1,01 = 1
Cl = 2,02/1,01 = 2
C₁O₁Cl₂ ≡ COCl₂
b) You need to find the molar mass of the empirical formula to determine the ratio of the real formula, thus:
1×C 12,01g/mol =
1×O 16 g/mol =
2×Cl 35,35g/mol = 98,91g/mol
As real molecular mass is 98,9 g/mol. The molecular formula: COCl₂
I hope it helps!
The bomb is filled with pure oxygen to ensure that sample in the bomb burns completely.
Oxygen is used for better combustion as it assists the burning process and increases heating system efficiency by reducing energy loss in exhaust gases.
If we use air instead of pure oxygen , rate of combustion will decrease because air contains only 21% of oxygen . Thus the efficiency will decrease and complete combustion will not take place.
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