I will mark brainliest 20 points

The length of a cell phone is 1.41.4 inches and the width is 4.44.4 inches. The company making the cell phone wants to make a ne

4vir4ik [10]

Answer:

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Step-by-step explanation:

swhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhq

7 0

3 years ago

I am lost on what to do

Neko [114]

$\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}$

$\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0$

4 0

4 years ago

The furniture store where Jada's sister works bought a table for $200 and sold it for $350. What percentage was the markup? I wa

nevsk [136]

Answer:

divide 350 by 200

Step-by-step explanation:

3 0

3 years ago

erry jogs the same round trip path everyday. He jogs 0.7 miles to the park and then 0.5 miles from the park to the playground. A

adelina 88 [10]

To solve this problem you must use the information given in the problem above:

1. You have that he jogs $0.7miles$ to the park and then $0.5miles$ to the playground, then he jogs $0.3$ miles to the bridge and $0.9miles$ to his house.