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3 years ago

3x3000=blank X blank X 1000= blank X 1 thousand = blank thousand

1 answer:

4 0

3 x 3000 = 9000 x blank x 1000 = blank x 1000 = blank000
im not too sure if there is anything specific you are supposed to fill in the other blanks with but from what you have provided i do believe you could use any number in the space of the first blank to fill out the rest of the equation. for example i you put 3 in the first blank space then the equation would write 3 x 3000 = 9000 x 3 x 1000 = 27000000 x 1000 = 27,000,000,000 but then this wouldnt work if on the question it says on the end thousand in writing. im sorry if this has not helped. if it does say thousand on the end comment below and i will reattempt this equation

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Answer:

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Step-by-step explanation:

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3 years ago

Can someone help me with these Algebra 1 questions, they are pretty tough and i need help since i don't fully understand it yet.

Hatshy [7]

I will answer second attachment and after since I can't see the firs attachment

2nd attachment

if x is negative, then the first number gets infinitely small
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3rd attachment
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4th attachment
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4 0

3 years ago

A total of 1680 ounces of pet food have to be packed in 5 pound bags. How many 5 pound bags of pet food can be packed ?

mamaluj [8]

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3 years ago

(115) the product of integers x, y, and z is even. is z even?

djyliett [7]

1. X/Y = Z

if x = 6, y = 2, then z = 3, not even

if x = 6, y = 3, then z = 2, even

<span>2. Z=XY </span>

so (z)^2 = 2*k (because x*y*z = 2k, where k is an integer)

<span>Sufficient, as if square of an integer is even ,then the integer is even</span>

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4 years ago

The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2617 and standard deviation

Eduardwww [97]

Answer:

a) N(2617, 586)

b) 0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c) 0.4013 = 40.13% of the customers consume over 2764 calories

d) 3981 calories.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 2617, \sigma = 586$

a. What is the distribution of X?

Here we first place the mean, then the standard deviation.

N(2617, 586)

b. Find the probability that the customer consumes less than 2409 calories.

This is the pvalue of Z when X = 2409. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2409 - 2617}{586}$

$Z = -0.355$

$Z = -0.355$ has a pvalue of 0.3613

0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c. What proportion of the customers consume over 2764 calories?

This is 1 subtracted by the pvalue of Z when X = 2764. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2764 - 2617}{586}$

$Z = 0.25$

$Z = 0.25$ has a pvalue of 0.5987

1 - 0.5987 = 0.4013

0.4013 = 40.13% of the customers consume over 2764 calories

d. The Piggy award will given out to the 1% of customers who consume the most calories. What is the fewest number of calories a person must consume to receive the Piggy award?

Top 1%, so the 100-1 = 99th percentile.

The 99th percentile is the value of X when Z has a pvalue of 0.99. So it is X when Z = 2.327. So

$Z = \frac{X - \mu}{\sigma}$

$2.327 = \frac{X - 2617}{586}$

$X - 2617 = 2.327*586$

$X = 3980.6$

Rounding to the nearest calorie, 3981 calories.

7 0

3 years ago