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Marizza181 [45]
3 years ago
13

I have no idea what to do

Mathematics
1 answer:
tekilochka [14]3 years ago
8 0

Answer: Y=-5x+30

Step-by-step explanation:

First, you have to find the slope of graph so you find the rise over run Y/X. Since the X values are being measured by 1’s, and the Y values are being measure by 5’s, your slope would be -5 (not 5 as the graph line is decreasing therefore it is negative). To find b, you find the Y intercept of the graph (where Y is when X=0) and in this case, the y intercept is 30. So the equation that describes what is occurring in the graph is Y=-5x+30 as a linear equation is written as Y=mx+b. You can check If the equation is correct by substituting the x and y values of a specific coordinate point on the graph. For example: 25= -5(1)+30. This gives you 25=25 so the equation is correct.

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Answer:

A) 7, 2

B) 1, 5

C) 6, 3

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The next term in a sequence Comes from adding the
Leno4ka [110]

Answer:

Step-by-step explanation:

Each new term is the sum of the two preceding terms.  Given 2, 9, etc., we see that a number between 2 and 9 is missing; call it x.  Then 2 + x must equal 9, and so x = 7, and so the first three terms are 2, 7, 9.  Repeating the process, we add 7 and 9, obtaining 16; thus the first four terms are 2, 7, 9, 16.  Continuing this pattern, we add 9 and 16 to obtain the fifth term, which is 25:  2, 7, 9, 16, 25.  And so on.

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Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.)
Salsk061 [2.6K]

Answer:

Mix fraction: 3 1/27

Improper fraction: 82/27

Decimal approximation: 3.037

Step-by-step explanation:

What value is close to 28 that is a perfect cube...27 which equals 3^3.

So let's find the tangent line to the curve y=cubert(x) at x=27.

We will use this equation to approximate what happens at x=28.

First let's rewrite the radical in our equation;

y=x^(1/3)

Now differentiate

y'=(1/3) x^(1/3-1) by power rule

Simplify

y'=(1/3) x^(-2/3) or (1)/(3x^[2/3])

So the slope of our tangent line at x=27 is (1)/(3(27)^[2/3])=1/(3(3)^2)=1/(3×9)=1/27.

We will also need a point on this tangent line....We know we have the point at x=27 because that is what our tangent line to curve is being found at.

So at x=27, we have y=cubert(27)=3. We used our equation y=cubert(x) here.

So we want to find the equation of the line that contains point (27,3) and has slope 1/27.

Point-slope form is

y-y1=m(x-x1)

Plug in our values

y-3=(1/27)(x-27)

Add 3 on both sides

y=3+(1/27)(x-27)

We will use this linear equation to approximate cubert(28) by replacing x with 28.

y=3+(1/27)(28-27)

y=3+(1/27)(1)

y=3+1/27

You can write that as a mix fraction if you want.

This value is than 3 but super close to 3 since 1/27 is close to 0.

Mix fraction: 3 1/27

Improper fraction: 82/27

Decimal approximation: 3.037

Cubert of 28 when smashed into calculator as is gives approximately 3.0366 which is pretty close to our approximation.

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Ghella [55]

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Answer:

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Step-by-step explanation:

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