Question

a student showed the steps below while solving the equation 14=log5(2x-3) by graphing. which step did the student make the 1sr error

Answer 1

Answer:

$x= \frac{5^{14}+3}{2}$

Step-by-step explanation:

The correct steps to solve the equation are:

$14=log_5(2x-5)$

$5^{14}=5^{log_5(2x-3)}$

Because $a^{log_am}=m$

So, solving we get:

$5^{14}=2x-3$

Sum 3 on every side:

$5^{14}+3=2x-3+3\\5^{14}+3=2x$

Dividing by 2 into both sides:

$\frac{5^{14}+3}{2}=\frac{2x}{2}\\\frac{5^{14}+3}{2}=x$

So, the answer is  $x= \frac{5^{14}+3}{2}$