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shusha [124]
3 years ago
12

a student showed the steps below while solving the equation 14=log5(2x-3) by graphing. which step did the student make the 1sr e

rror
Mathematics
1 answer:
mixer [17]3 years ago
7 0

Answer:

x= \frac{5^{14}+3}{2}

Step-by-step explanation:

The correct steps to solve the equation are:

14=log_5(2x-5)

5^{14}=5^{log_5(2x-3)}

Because a^{log_am}=m

So, solving we get:

5^{14}=2x-3

Sum 3 on every side:

5^{14}+3=2x-3+3\\5^{14}+3=2x

Dividing by 2 into both sides:

\frac{5^{14}+3}{2}=\frac{2x}{2}\\\frac{5^{14}+3}{2}=x

So, the answer is  x= \frac{5^{14}+3}{2}

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How many rows of seats are needed to seat 673 people at a concert when the rows seat 37 people each?
Rasek [7]

Answer:

18.189 rows

Step-by-step explanation:

673 / 37 = 18.189189189

Hope this helps!

5 0
3 years ago
Considere a função de oferta como sendo y= 5x - 1/2 e a função de demanda como sendo y= -7x + 47/2 , onde x é a quantidade e y é
swat32

A) Temos que igualar isso a 2,50, que é o valor de y, ou seja, o valor do preço. Façamos isso, então, na função de demanda.

y = -7x + \frac{47}{2}

Substituir.

2,50 = - 7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x  = - \frac{47}{2} + 2,50

A fração 47/2 corresponde a 23,5. É mais interessante para nós, nesse caso, utilizar o valor decimal.

-7x  = - 23,5 + 2,50

Somar logo.

-7x = -21

Podemos multiplicar por -1 para tirar os sinais negativos.

7x = 21

Passar o x dividindo

x = \frac{21}{7}

Dividir

\boxed{x = 3}

Para um preço de R$ 2,50, a quantidade demandada é de 3 unidades.



B) Basta igualar as duas formulinhas.

5x - \frac{1}{2} = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x + 7x = \frac{47}{2} + \frac{1}{2}

Somar tudo. Como as frações têm o mesmo denominador, <u>nada de </u><u>mmc</u>! Basta somar os numeradores.

12x = \frac{48}{2}

Podemos dividir lá, olha:

12x = 24

Passar o x dividindo

x = \frac{24}{12}

Dividir

\boxed{x = 2}

O ponto de equilíbrio é o valor 2.



C) Basta, então, igualar as fórmulas da oferta e da demanda a 10.

Fórmula da oferta

10 = 5x - \frac{1}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x = 10 - \frac{1}{2}

Se 1/2 = 0,5, dá pra resolver sem fazer mmc:

5x = 10 - 0,5

Subtrair

5x = 9,5

Passar dividindo

x = \frac{9,5}{5}

Dividir.

\boxed{x = 1,9}

Fórmula da demanda

10 = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x = \frac{47}{2} - 10

Divide 47/2, vai.

-7x = 23,5 - 10

Subtrair.

-7x = 13,5

Passar o 7 dividindo.

x = - \frac{13,5}{7}

Vamos dividir e transformar em decimal.

\boxed{x = -1,9285714285714285714285714285714}


Subtrair a oferta pela demanda.

x = 1,9 - (-1,9285714285714285714285714285714)

Subtrair.

\boxed{x = 3,8285714285714285714285714285714}

Arredondando, o preço será de R$ 3,83.

8 0
3 years ago
“ it will take 1 2/3 hours” what is the 2/3 in minutes ?
Fittoniya [83]

Answer:

40 minutes

Step-by-step explanation:

2/3 x 60 = 40

8 0
3 years ago
Write an absolute value equation to satisfy the given solution set shown on a number line.
aivan3 [116]

Answer: IX - 4I ≤ 4

Step-by-step explanation:

In the numer line we can see that our possible values of x are in the range:

0 ≤ x ≤ 8

And we want to find an absolute value equation such that this set is the set of possible solutions.

An example can be:

IX - 4I ≤ 4

To construct this, we first find the midpoint M of our set, in this case is 4.

Then we write:

Ix - MI  ≤ IMI

Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the <  > signs.

8 0
3 years ago
Algebra 2 need help on a ( ABC )
Len [333]

Answer:

b)

x =  \frac{15}{4}

Step-by-step explanation:

b) set up equations so they are equal to each other,

2x - 2 =  - 3x + 12

5x = 14

x = \frac{14}{5}

this is when f(x)=g(x) so our approximation was close.

c)solving it graphically is nearly impossible because the solution can be any value around the intersection. only way to be sure is to solve it symbolically.

3 0
3 years ago
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